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mullacllahdoow
Rank #16700 on Comments
Level 231 Comments: Ambassador Of Lulz
Online
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Last status update:

Gender:
male
Age:
26
Date Signed Up:
7/21/2011
Last Login:
2/21/2017
Stats
Comment Ranking:
#16700
Highest Content Rank:
#6109
Highest Comment Rank:
#2732
Content Thumbs:
26
total, 38
, 12
Comment Thumbs:
3619
total, 3746
, 127
Content Level Progress:
42.37% (25/59)
Level 0 Content: Untouched account → Level 1 Content: New Here
Comment Level Progress:
1% (1/100)
Level 231 Comments: Ambassador Of Lulz → Level 232 Comments: Ambassador Of Lulz
Subscribers:
0
Content Views:
3863
Times Content Favorited:
1 times
Total Comments Made:
579
FJ Points:
3122
What people say about mullacllahdoow
latest user's comments
#22
 ok, no... W*2/W = 2 W^2/W = W... a * denot…
[+]
(9 replies)
05/14/2015 on
Happiness
+1
#51

athale
(05/14/2015)
[]
i did not understand thanks for explaining
#25

icewraithking
(05/14/2015)
[]
i swear im getting retarded everyday, i should stop surrounding myself with retarded people
#26

mullacllahdoow
(05/14/2015)
[]
no sweat man, maths is my thing, unfair advantage
#38

tolikbro
(05/14/2015)
[]
Set W=T
It just depends on whether you decide to do W*W or W+W.
In the first case, two women = T^2
In the second case, two women = 2T
Trouble squared or twice the trouble, all depends on how you want to combine the women.
#40

mullacllahdoow
(05/14/2015)
[]
and W*2 = W+W... what I said was for
W*2 = W^2 that requires W=2 and hence T=2
again, is was supposed to be a joke... but since everyone is so insistant that I'm wrong.
for a relationship for increasing women linearly to result in exponential growth of trouble you'd require:
let T = trouble and let T=x i.e. a large number representing trouble caused by 1 woman. then:
T = x^W
i.e. for 2 women: T = x^2
for 3 women T= x^3
etc...
The original post said W*2 (i.e. W+W) = T^2. Not mathematically correct if T=W.
#49

mullacllahdoow
has deleted their comment.
#48

racetothebottom
(05/14/2015)
[]
jesus christ you're all missing the point
W is not equal to T
W and T are related, but that doesn't mean they're equal
like please point out where the first comment said W=T
W*x = T^x
is that so difficult to understand?
#50

mullacllahdoow
(05/14/2015)
[]
Where he said "a woman is trouble" I was literally just making a "funny" (clearly not funny) observation from a mathematical standpoint. I didn't mean to start a debate on the difference between linear and exponential relationships and how to properly define said relationship.
I understood what he was getting at
#52

athale
(05/14/2015)
[]
... math wizards are debating my comment
#14
 T^2 = T * T if T = W and T^2 = W*2 then W*2 …
[+]
(14 replies)
05/14/2015 on
Happiness
+1
#53

anon
(05/15/2015)
[]
Guys, no one said W=T
#19

icewraithking
(05/14/2015)
[]
you divided wrong, its ((w*2)/w)=w ,
also
here is a nifty site to do that,
www.wolframalpha.com/
#23

mullacllahdoow
(05/14/2015)
[]
Also, you might want to check what your own source tells you before you tell me I'm wrong
www.wolframalpha.com/input/?i=%28w*2%29%2Fw
#24

icewraithking
(05/14/2015)
[]
well shit.
#22

mullacllahdoow
(05/14/2015)
[]
ok, no... W*2/W = 2
W^2/W = W...
a * denotes multiply.
Source. I have a Maths degree. also... my reply was (clearly a bad) attempt at humour. not intended to be analysed.
#51

athale
(05/14/2015)
[]
i did not understand thanks for explaining
#25

icewraithking
(05/14/2015)
[]
i swear im getting retarded everyday, i should stop surrounding myself with retarded people
#26

mullacllahdoow
(05/14/2015)
[]
no sweat man, maths is my thing, unfair advantage
#38

tolikbro
(05/14/2015)
[]
Set W=T
It just depends on whether you decide to do W*W or W+W.
In the first case, two women = T^2
In the second case, two women = 2T
Trouble squared or twice the trouble, all depends on how you want to combine the women.
#40

mullacllahdoow
(05/14/2015)
[]
and W*2 = W+W... what I said was for
W*2 = W^2 that requires W=2 and hence T=2
again, is was supposed to be a joke... but since everyone is so insistant that I'm wrong.
for a relationship for increasing women linearly to result in exponential growth of trouble you'd require:
let T = trouble and let T=x i.e. a large number representing trouble caused by 1 woman. then:
T = x^W
i.e. for 2 women: T = x^2
for 3 women T= x^3
etc...
The original post said W*2 (i.e. W+W) = T^2. Not mathematically correct if T=W.
#49

mullacllahdoow
has deleted their comment.
#48

racetothebottom
(05/14/2015)
[]
jesus christ you're all missing the point
W is not equal to T
W and T are related, but that doesn't mean they're equal
like please point out where the first comment said W=T
W*x = T^x
is that so difficult to understand?
#50

mullacllahdoow
(05/14/2015)
[]
Where he said "a woman is trouble" I was literally just making a "funny" (clearly not funny) observation from a mathematical standpoint. I didn't mean to start a debate on the difference between linear and exponential relationships and how to properly define said relationship.
I understood what he was getting at
#52

athale
(05/14/2015)
[]
... math wizards are debating my comment
#5
 I don't see what you're trying to say... if W=T and W*2 = T^2 …
[+]
(17 replies)
05/13/2015 on
Happiness
8
#13

icewraithking
(05/14/2015)
[]
you failed at math?
you dont simplify it that way
#14

mullacllahdoow
(05/14/2015)
[]
T^2 = T * T
if T = W and T^2 = W*2 then
W*2 = T * T at this point it's obvious that W=T=2 but:
Since W = T we can sub T for W on the right hand side giving
W*2 = W*W
divide through by W to get
2 = W as I stated.
#53

anon
(05/15/2015)
[]
Guys, no one said W=T
#19

icewraithking
(05/14/2015)
[]
you divided wrong, its ((w*2)/w)=w ,
also
here is a nifty site to do that,
www.wolframalpha.com/
#23

mullacllahdoow
(05/14/2015)
[]
Also, you might want to check what your own source tells you before you tell me I'm wrong
www.wolframalpha.com/input/?i=%28w*2%29%2Fw
#24

icewraithking
(05/14/2015)
[]
well shit.
#22

mullacllahdoow
(05/14/2015)
[]
ok, no... W*2/W = 2
W^2/W = W...
a * denotes multiply.
Source. I have a Maths degree. also... my reply was (clearly a bad) attempt at humour. not intended to be analysed.
#51

athale
(05/14/2015)
[]
i did not understand thanks for explaining
#25

icewraithking
(05/14/2015)
[]
i swear im getting retarded everyday, i should stop surrounding myself with retarded people
#26

mullacllahdoow
(05/14/2015)
[]
no sweat man, maths is my thing, unfair advantage
#38

tolikbro
(05/14/2015)
[]
Set W=T
It just depends on whether you decide to do W*W or W+W.
In the first case, two women = T^2
In the second case, two women = 2T
Trouble squared or twice the trouble, all depends on how you want to combine the women.
#40

mullacllahdoow
(05/14/2015)
[]
and W*2 = W+W... what I said was for
W*2 = W^2 that requires W=2 and hence T=2
again, is was supposed to be a joke... but since everyone is so insistant that I'm wrong.
for a relationship for increasing women linearly to result in exponential growth of trouble you'd require:
let T = trouble and let T=x i.e. a large number representing trouble caused by 1 woman. then:
T = x^W
i.e. for 2 women: T = x^2
for 3 women T= x^3
etc...
The original post said W*2 (i.e. W+W) = T^2. Not mathematically correct if T=W.
#49

mullacllahdoow
has deleted their comment.
#48

racetothebottom
(05/14/2015)
[]
jesus christ you're all missing the point
W is not equal to T
W and T are related, but that doesn't mean they're equal
like please point out where the first comment said W=T
W*x = T^x
is that so difficult to understand?
#50

mullacllahdoow
(05/14/2015)
[]
Where he said "a woman is trouble" I was literally just making a "funny" (clearly not funny) observation from a mathematical standpoint. I didn't mean to start a debate on the difference between linear and exponential relationships and how to properly define said relationship.
I understood what he was getting at
#52

athale
(05/14/2015)
[]
... math wizards are debating my comment
#6

athale
(05/13/2015)
[]
im saying one woman is trouble but two woman isn't double trouble its trouble squared
#59
 Right... must be it.
[+]
(1 reply)
05/12/2015 on
500 words per minute
+1
#193

anon
(08/30/2015)
[]
Bc you're all faggot ass bitches.
Cunt.
#49
 In my last job, we tried Spritzing to read technical documents…
[+]
(3 replies)
05/12/2015 on
500 words per minute
+3
#55

anon
(05/12/2015)
[]
Soooo.... what you're telling me is that you were all too dumb to use Spritzing?
#59

mullacllahdoow
(05/12/2015)
[]
Right... must be it.
#193

anon
(08/30/2015)
[]
Bc you're all faggot ass bitches.
Cunt.
#12
 Uh huh, I also heard there is a shorter version where we never…
05/11/2015 on
Choices, choices
0
#10
 hydrophobic carpet, wine leaves through the catflap.
05/09/2015 on
Fuck yo stain nigga
+3
#14
 sounds ridiculous...
[+]
(1 reply)
05/09/2015 on
Cutthroat Buisness or is it
0
#15

Taliesin
(05/09/2015)
[]
It totally is, but understandable. Ish.
#12
 Hey I don't disbelieve you, but if this is the case, would the…
[+]
(3 replies)
05/09/2015 on
Cutthroat Buisness or is it
0
#13

Taliesin
(05/09/2015)
[]
Yup, she'd be fined on average around 100200 dollars for a facial expression. I'm not sure where this happened or who she works for, but the company I worked for fined 200 for facial changes short of smiling, 300400 for smiling, 600 for frowning, and on from there. It was brutal.
#14

mullacllahdoow
(05/09/2015)
[]
sounds ridiculous...
#15

Taliesin
(05/09/2015)
[]
It totally is, but understandable. Ish.
#113
 the chance for two crits would be 25%... 0.5x0.5 = 0.25. …
05/06/2015 on
Has to be 50%
0
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