mindclaw
Rank #16930 on Comments
Level 239 Comments: Ambassador Of Lulz Online
Send mail to mindclaw Block mindclaw Invite mindclaw to be your friend Last status update:  

 
Date Signed Up:  11/03/2012 
Last Login:  7/27/2016 
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latest user's comments
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#166 
anon (12/02/2015) [] I have a like "super computer" calculator with colors and all that, it cost me 200$. It gives me the answer of 9. (Which is incorrect) As far as I know every calculator should give the wrong answer of 9. Yours is magical like I can't explain why yours gives the right answer.. #170 
anon (12/02/2015) [] If you have Windows 8 or 10, try using it's calculator. It'll always say 9 #172 
anon (12/02/2015) [] I guess it's just simply too hard to code correctly. You'd imagine that with the modern technology that they'd be able to fix such an error. People rely too heavily on calculators. #153 
enferax (12/02/2015) [] First problem: no multiplikation symbol a(b+c) = a*(b+c) => a : b(c+d) = a : b * (c+d) != a : (b * (c+d) second problem: division a : b * c = (a:b)*c != a : (b*c) = a : b : c a  b + c = (ab)+c != a  (b+c) = a  b  c this makes 6 : 2(1+2) = 6 : 2 * 3 = (6:2) * 3 = 3 * 3 = 9 Unfortunately I'm too lazy to show the higher math behind it (easy in german, hard in non native language) but if someone is interested just search for "Multiplicative Inverse Axiom" #160 
andra (12/02/2015) [] heres my reasoning you treat the parentheses as a variable before you know the result of them because coefficients work the same way for both 6/2x =/= 3x its 3x^1 so you wouldnt get 9 if you put x back in with 3x^1 then that's 3/3 = 1 the order of operations means you work out parentheses first and coefficients are the same term as the parentheses so again you multiply first #174 
enferax (12/02/2015) [] Please don't ignore that a : b(c+d) = a : b * (c+d) != a : (b * (c+d). I took another example with 8 : 2 * 2 = 8 to show this. Using your argumentation we would have 8 / (2 * 2) = 2 which is wrong. There is something called left associative operation which is the standard way of interpretation if not stated otherwise. The problem here is that the way you used might not be wrong in terms of mathematical theorems but it is in mathematical associative axioms. #177 
enferax (12/02/2015) [] b(c+d) =/= b * (c+d) b(c+d) == (b* (c+d)) And again, this isn't stated in the original term. It states: 6 : 2(1+2)=? a : b(c+d) = a : b * (c+d) = ? a : b * e = ? This is what you have to do using the left associative operation  which you have to do unless stated otherwise (using brakets). Yours would have been stated as 6 : (2(1+2))=? #185 
enferax (12/02/2015) [] So there is another operator for you besides +,,* and : which gives a different meaning than *? Because I only know these four. Don't misinterpret this as beeing cocky or anything. I'm really enjoying this conversation as your arguments are strong and clearly understandable while beeing based on math. The thing is, that your operator states that a*(b+c) != a(b+c) #159 
enferax (12/02/2015) [] And the mathematical conclusion: The Multiplicative Inverse Axiom states that the product of a real number and its multiplicative inverse is 1. Every real number has a unique multiplicative inverse. The reciprocal of a nonzero number is the multiplicative inverse of that number. Reciprocal of x is 1/x. x * 1/x = 1. x * x´ = 1 for x´ = 1/x Typical notations for x´ are x^1 or 1/x. The division is defined as multiplication with the inverse of the divisor. So a : b * c = a * b^1 * c != a * b^1 * c^1 = a : b : c = a : (b:c). And for us 6 : 2 * (1 + 2) = 6 : 2 * 3 = 6 * 2^1 * 3= 6 * 1/2 * 3 = 9  
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