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mindclaw

Last status update:
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Date Signed Up:11/03/2012
Last Login:12/08/2016
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Content Thumbs: 1998 total,  2716 ,  718
Comment Thumbs: 5056 total,  5237 ,  181
Content Level Progress: 98% (98/100)
Level 119 Content: Funny Junkie → Level 120 Content: Respected Member Of Famiry
Comment Level Progress: 33% (33/100)
Level 239 Comments: Ambassador Of Lulz → Level 240 Comments: Doinitrite
Subscribers:3
Content Views:144812
Total Comments Made:317
FJ Points:5956

latest user's comments

#40 - Picture  [+] (6 replies) 12/07/2015 on Chinese cartoon were an... +11
#47 - tyguru (12/07/2015) [-]
Sauce please... I've been searching for half an hour
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#112 - cormy (12/07/2015) [-]
iqdb.org
Abuse it
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#89 - gustaforce (12/07/2015) [-]
very nice
#52 - tyguru (12/07/2015) [-]
Thank you so much
#58 - anon (12/07/2015) [-]
its easy if you beter check gelbooru, one punch man, google it ;)
#6 - Picture 12/05/2015 on Anon dresses up +37
#135 - **** Casio  [+] (24 replies) 12/02/2015 on Can FJ do basic math? +2
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#148 - andra (12/02/2015) [-]
well mines more recent so they probs changed it between the two
thats weird though
like someone just changed how maths works
#166 - anon (12/02/2015) [-]
I have a like "super computer" calculator with colors and all that, it cost me 200$.
It gives me the answer of 9.
(Which is incorrect)

As far as I know every calculator should give the wrong answer of 9.

Yours is magical like I can't explain why yours gives the right answer..
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#168 - andra (12/02/2015) [-]
because it knows what terms are
#170 - anon (12/02/2015) [-]
If you have Windows 8 or 10, try using it's calculator.
It'll always say 9
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#171 - andra (12/02/2015) [-]
its because you have to type the x symbol in
and the programming has it go left to right with multiplication and division so it you divide by 2 first
it treats it like a seperate term shit doesnt work
#172 - anon (12/02/2015) [-]
I guess it's just simply too hard to code correctly.
You'd imagine that with the modern technology that they'd be able to fix such an error.

People rely too heavily on calculators.
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#153 - enferax (12/02/2015) [-]
First problem: no multiplikation symbol

a(b+c) = a*(b+c)

=> a : b(c+d) = a : b * (c+d) != a : (b * (c+d)

second problem: division

a : b * c = (a:b)*c != a : (b*c) = a : b : c
a - b + c = (a-b)+c != a - (b+c) = a - b - c

this makes

6 : 2(1+2) = 6 : 2 * 3 = (6:2) * 3 = 3 * 3 = 9

Unfortunately I'm too lazy to show the higher math behind it (easy in german, hard in non native language) but if someone is interested just search for "Multiplicative Inverse Axiom"
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#154 - andra (12/02/2015) [-]
if theres no multiplication symbol it's a coefficient and you treat it as one term
so you have to multiply before you divide
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#157 - enferax (12/02/2015) [-]
One term. So a : b * (c+d) = a : b *d for d = c+d. From there it's nothing but left to right as division is multiplikation with the inverse. There is no division before multiplikation rule as it is the same function.
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#158 - enferax (12/02/2015) [-]
Sorry. It's a : b * (c+d) = a : b *e for e = c+d
#160 - andra (12/02/2015) [-]
heres my reasoning
you treat the parentheses as a variable before you know the result of them
because coefficients work the same way for both
6/2x =/= 3x
its 3x^-1
so you wouldnt get 9
if you put x back in with 3x^-1 then that's 3/3 = 1
the order of operations means you work out parentheses first and coefficients are the same term as the parentheses
so again
you multiply first
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#164 - enferax (12/02/2015) [-]
Well 6 : 2 * x = 6 : 2x but not 6 : (2 * x).

8 : 2 * 2 is 8 not 2.
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#165 - andra (12/02/2015) [-]
what
2x is the same thing as 2*x but in the same term
which also applies for coefficients
and i didnt write 8 anywhere
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#167 - andra (12/02/2015) [-]
parentheses* not coefficients
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#174 - enferax (12/02/2015) [-]
Please don't ignore that a : b(c+d) = a : b * (c+d) != a : (b * (c+d).

I took another example with 8 : 2 * 2 = 8 to show this. Using your argumentation we would have 8 / (2 * 2) = 2 which is wrong. There is something called left associative operation which is the standard way of interpretation if not stated otherwise. The problem here is that the way you used might not be wrong in terms of mathematical theorems but it is in mathematical associative axioms.
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#176 - andra (12/02/2015) [-]
b(c+d) =/= b * (c+d)
b(c+d) == (b* (c+d))
ignore the other one
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#177 - enferax (12/02/2015) [-]
b(c+d) =/= b * (c+d)
b(c+d) == (b* (c+d))

And again, this isn't stated in the original term. It states:

6 : 2(1+2)=?
a : b(c+d) = a : b * (c+d) = ?
a : b * e = ?

This is what you have to do using the left associative operation - which you have to do unless stated otherwise (using brakets).

Yours would have been stated as
6 : (2(1+2))=?
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#178 - andra (12/02/2015) [-]
yes and thats what's implied
it doesnt say 2*(1+2) it says 2(1+2)
and likewise its not b*e its be
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#185 - enferax (12/02/2015) [-]
So there is another operator for you besides +,-,* and : which gives a different meaning than *? Because I only know these four. Don't misinterpret this as beeing cocky or anything. I'm really enjoying this conversation as your arguments are strong and clearly understandable while beeing based on math.

The thing is, that your operator states that a*(b+c) != a(b+c)
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#198 - enferax (12/02/2015) [-]
Andra: As I can't reply to #190 :

The definition of a coefficient alway has the word multiplication in it and doesn't differ from the form a*x = ax.
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#190 - andra (12/02/2015) [-]
its not really its own operator
more like algebraic notation
a coefficient is different to just multiplying because of the order
coefficients always come first
#175 - andra has deleted their comment.
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#159 - enferax (12/02/2015) [-]
And the mathematical conclusion:

The Multiplicative Inverse Axiom states that the product of a real number and its multiplicative inverse is 1. Every real number has a unique multiplicative inverse. The reciprocal of a nonzero number is the multiplicative inverse of that number. Reciprocal of x is 1/x. x * 1/x = 1. x * x´ = 1 for x´ = 1/x

Typical notations for x´ are x^-1 or 1/x. The division is defined as multiplication with the inverse of the divisor. So a : b * c = a * b^-1 * c != a * b^-1 * c^-1 = a : b : c = a : (b:c).
And for us 6 : 2 * (1 + 2) = 6 : 2 * 3 = 6 * 2^-1 * 3= 6 * 1/2 * 3 = 9
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#163 - andra (12/02/2015) [-]
youre still implying that the 2 and (1+2) aren't the same term
when they are
its not 6 * 2^-1 * (2+1) its 6 * (2(1+2))^-1
#4 - praise the lord 11/24/2015 on 7 YEARS 0