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hpnerd

Last status update:
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Date Signed Up:7/28/2011
Last Login:11/28/2016
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Content Thumbs: 1844 total,  2416 ,  572
Comment Thumbs: 920 total,  1312 ,  392
Content Level Progress: 44% (44/100)
Level 118 Content: Funny Junkie → Level 119 Content: Funny Junkie
Comment Level Progress: 80% (8/10)
Level 191 Comments: Anon Annihilator → Level 192 Comments: Anon Annihilator
Subscribers:1
Content Views:75596
Times Content Favorited:99 times
Total Comments Made:416
FJ Points:2773
Favorite Tags: fail (3) | challenge accept (2) | close enough (2) | comic (2) | derp (2) | Food (2) | meme (2)

Text Posts

latest user's comments

#18 - It's. So. ****. The words don't fit with the rhythm a…  [+] (1 reply) 11/16/2013 on FunnyJunk intro +35
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#25 - timmywankenobi (11/17/2013) [-]
I was just thinking the same thing.
#179 - Over 93% of the UK is covered in wilderness  [+] (1 reply) 11/10/2013 on one of the rarerst pictures... 0
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#182 - randomituseddie (11/10/2013) [-]
wow, it never really seems like that much, all the cities seem so huge.
#30 - That is not their velocity because it is the cos angle times g…  [+] (4 replies) 10/26/2013 on which car enters first? 0
#33 - guywithapen (10/26/2013) [-]
Ok, or you could use velocity = initial speed^2 + (2 * acceleration(gravity) * distance to the finish line).
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#55 - anniethreeone (10/26/2013) [-]
This problem can't be done using kinematic equations since the slope of the incline is changing. You need to use calculus, and the answer is not intuitive. It's a parametric equation that looks like nonsense and took Issac Newton 12 hours working through the night to come up with.

en.wikipedia.org/wiki/Brachistochrone_curve
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#49 - mrspok (10/26/2013) [-]
I thought the acceleration would be 3.8M^2/s until terminal volatility is achieved, assuming that they are on earth of course and that there is a wind speed of 0 as in a vacuum chamber. 1 and 2 would tie, as car 3 dips below the finish and will lose energy and slow at the up hill part.
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#52 - mrspok (10/26/2013) [-]
given that we have only partial data, we would need to know the weight of each car and the length of at least one of the tracks