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Level 23 Comments: Peasant
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#21 - anonymous (12/18/2012) [-]
Not true. .9999999... is an indeterminate value. You can say
lim x->infinity of a sum that models .999999... equals 1 but there IS a distinction between limits and values. .9999999 cannot equal 1 in the real world but in fact is infinitely close to one. however the limit is the same so in calculus by applying limits we can treat them as the same number.
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#13 - jbkubel (12/17/2012) [-]
You're wrong, what y ou are dealing with to get one, is 0.3333333 ... (this will continue you on for infinity, but at the ''end'' there will be a 4) ... 3333333334
The third of 0.999 is 0.333 which is correct, but not 0,333333334 .
I hope you get what I'm saying here, otherwise I'll send you a more detailed explanation.
#19 - anonymous (12/18/2012) [-]
x = .999999....
10x = 9.999999.......
10x - x = 9.999999...... - .999999......
9x = 9
x = 1
That's the proof. Stop spouting nonsense.
#23 - howaboutnsfw (12/18/2012) [-]
Technically not true...
When you subtract the numbers, x will have one more decimal place beyond 10x at every given extent. The limitation is how many decimal points to you consider significant, but no mater where that is. So really you are left with an infinitely small remainder which you ignore.
Just how you would expect it to...
#44 - prettyfire (12/20/2012) [-]
butbutbut... why would x have one more decimal place? They both have the same number of decimal places, because they both have infinite decimal places. And why would ANYONE expect 0.9-0.9 to be 0.01? Because even though there are more 9's and more 0's, that's basically what it comes out to.
#14 - jbkubel (12/17/2012) [-]
Another explanation worth menitioning, is that 0.9999999 is a number in the infinite world, while 1 is the number in the finite world thus prooving they are not the same number, they aren't even in the same categories of number. 0.99999... Is not even an existing number in that sense.
#22 - lordbyronxiv (12/18/2012) [-]
e^(ipi) = -1 where i = imaginary unit and pi = the irrational ratio of a circle's diameter to its circumference (pi=c/d)
there are several transformations that take numbers from one "category" to the next.
truth is .9... (.9 continuous) exactly equals .1.
math is the real world.
#34 - jbkubel (12/18/2012) [-]
This is however true, but if we deal with math, as you say it is now, then the number one simply doesn't exist. It doesn't because there wouldn't be anything that would, in the real world, be 1 unit long, since you will always be able to put on more and more decimals on.
So in theory, 1 = 0.999...
However in the real world, the finite world, 1 > 0.999.. and 0.999... Will end at some point. This is what we use in the real world. Of course math is a theory, and this problem is known as a mathmatical paradox, however at some point you have to make a decission, and look at whether or not it's 1 or < than one. At some point, 0.999... Will get so close to one, that there would quite litteraly be nothing in between other than theory. If you look at it from the perspective of the real world, of us right now, you would at some point get so close to 1, even atoms would be too big to be there.
Therefor it is in practical math, that 0.999... < 1 so it is the only sensible thing to have accordingly to what is both logical, and what it is practical.
To end off, the infinite world, really doesn't exist, becuase we don't use it. I know my logic here is flawed, but math it self would litteraly be impossible to deal with in any way, shape or form, if we used the infinite world.
#41 - jbkubel (12/20/2012) [-]
As I tried to explain above, I get your point and if we deal with the infinite mathmatical world, then you are right. However we don't. We ude math as being finite, because if we didn't then we wouldn't be able to use math in the first place.
- I get your point, and you are just as right as I am. I've given all my arguments, and I'm therefore done with this discussion. Have a good day sir.
#18 - anonymous (12/18/2012) [-]
Please educate yourself.