its like fucking chinese. . 2 First of all, my example shows that if you take two generic upper triangular matrices A and B of size 9, then AS, are linearly ind
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its like fucking chinese

2 First of all, my example shows that if you take two generic upper triangular matrices A and B of size 9, then
AS, are linearly independent. I suspect that in fact EA would also be independent from them in this
case, but I did not check it. I also think that taking V to be a generic dimension two subspace of
upper triangular size 4 matrices, would give V 2 3 (elements of V 2 can only have three
possible nonzero entries, but I see no reason for why the span ofthem would be any less than that). -
Lev IE hours ago
I believe that every subspace V can be conjugated inside the space of upper triangular matrices,
regardless of your assumption on dimensions of V I So they will have a common invariant zero eigenstate-
Lev IE hours ago
I Thanks for your further explanations, considerations with generic spaces seem helpful. Concerning the
second comment, unfortunately, there are spaces V not equivalent to triangular matrices; for
instance, that spanned MA = (iii 31) and B = (I 3 3) holds this property because AB has a
ponyzero eigenvalue. - IE hours ago
Thank you, this is a nice example. I got fooled by my commutative heritage. - Lev hours ago
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Submitted: 08/03/2014
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User avatar #2 - banjodance (08/03/2014) [-]
hell yea adblock ftw
User avatar #1 - turkeyslapper ONLINE (08/03/2014) [-]
Linear Algebra, I ******* hated this subject in uni.
User avatar #3 - stabbedinthecrotch (08/03/2014) [-]
Can't do electrical engineering without linear algebra. Which includes building the computer on which OP is being a faggot.
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