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Idiot
By: dagrizzlybear
3 x 3 = 12
Tags: yupp
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q I its 1 you do first then multiply the
2 by the sum of that owning you 6 which then makes
it are
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El 393 people like this,
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I killall, mi "Like
minutes ago Li
q I its 1 you do first then multiply the
2 by the sum of that owning you 6 which then makes
it are
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What do you think? Give us your opinion. Anonymous comments allowed.
#54

thesoulless (03/23/2013) [+] (2 replies)
Instructions not clear enough, got dick stuck in calculator.
#307

anonymous (03/23/2013) [+] (9 replies)
Okay there's a lot of confusion being caused here by the bad syntax in the question and by the looks of things, people not being properly taught the application of PEMDAS. I'll try and break it down as much as possible and explain why we use these forms and orders.
Firstly, the important thing to note is that the posed question: 6/2(1+2) does not have an operator between the '2' and '(1+2)'. This very simple little thing is what's causing your application of PEMDAS to go awry. Consider for a moment the similar problem: 8/(6x+2y) which we can simplify by taking out the common factor as 8/2(3x+y). Now if you apply PEMDAS assuming that the 2(3x+y) is the same as 2*(3x+y) you'll get an incorrect answer.
Cont. below.
Firstly, the important thing to note is that the posed question: 6/2(1+2) does not have an operator between the '2' and '(1+2)'. This very simple little thing is what's causing your application of PEMDAS to go awry. Consider for a moment the similar problem: 8/(6x+2y) which we can simplify by taking out the common factor as 8/2(3x+y). Now if you apply PEMDAS assuming that the 2(3x+y) is the same as 2*(3x+y) you'll get an incorrect answer.
Cont. below.
#308 to #307

anonymous (03/23/2013) []
This is because when you have 2(f(x)) is is shorthand for (2.(f(x)))  why the extra brackets? Simply because that 2 'belongs' to the bracket. In high school you will probably get away with using 'classroom shorthand' meaning 2*(1+2) which is not strictly correct. If the f(x) were a vector then it would be equivalent to 2.(V) which gives a scalar and so must go first (you cannot divide by a vector.)
This is why you're getting a 9. Cont below.
It's probably simpler for you to think of the '2' of (1+2) as 'belonging' to the bracket and so it gets resolved during out first parentheses stage. Hence
6/2(1+2)
=6/2(3)
=6/6
=1
You might also like to think of 2(1+2) as being equivalent to (2*(1+2)) rather than simply 2*(1+2)  which would have to have been written as such for it to apply in the same way as the division sign  so that your PEMDAS application can be rigidly applied. This is also the cause of error when putting it into a calculator because it relies on you spotting this.
This is why you're getting a 9. Cont below.
It's probably simpler for you to think of the '2' of (1+2) as 'belonging' to the bracket and so it gets resolved during out first parentheses stage. Hence
6/2(1+2)
=6/2(3)
=6/6
=1
You might also like to think of 2(1+2) as being equivalent to (2*(1+2)) rather than simply 2*(1+2)  which would have to have been written as such for it to apply in the same way as the division sign  so that your PEMDAS application can be rigidly applied. This is also the cause of error when putting it into a calculator because it relies on you spotting this.
#400

Snookbone ONLINE (03/23/2013) []
Well in Britain our equivalent of PEMDAS is BIDMAS, Brackets (or parentheses), Indices, Division&Multiplication, Addition&Subtraction.
Therefore, you deal with the brackets first, and then divide.
Ergo, 2(1+2)= 6
6/6=1
Therefore, you deal with the brackets first, and then divide.
Ergo, 2(1+2)= 6
6/6=1
#164

crilleballe (03/23/2013) [+] (4 replies)
6 / 2 ( 1 + 2 ) = x <=>
6 / 2 (3) = x
Now what? Do we divide 6 by 2 first, or multiply 2 with 3 first?
If you follow what's called "implied multiplication", then you would multiply 2 with 3 first, since there is no multiplication sign.
With implied multiplication, " 1/2x " would be the same as " (1/2) * x "
Without implied multiplication " 1/2x " would be the same as " 1 / (2x) "
So if x was equal to 4, " 1 / 2x " could be both (1/2) * x = 2 or 1 / (2x) = 0.125
The same way, 6 / 2 ( 1 + 2 ) could both be:
6 / 2 ( 1 + 2 ) = x <=>
6 / 2 (3) = x <=>
6 / 6 = x <=>
1 = x
with implied multiplication, or
6 / 2 ( 1 + 2 ) = x <=>
3 ( 1 + 2 ) = x <=>
3 ( 3 ) = x <=>
9 = x
Without implied multiplication.
6 / 2 (3) = x
Now what? Do we divide 6 by 2 first, or multiply 2 with 3 first?
If you follow what's called "implied multiplication", then you would multiply 2 with 3 first, since there is no multiplication sign.
With implied multiplication, " 1/2x " would be the same as " (1/2) * x "
Without implied multiplication " 1/2x " would be the same as " 1 / (2x) "
So if x was equal to 4, " 1 / 2x " could be both (1/2) * x = 2 or 1 / (2x) = 0.125
The same way, 6 / 2 ( 1 + 2 ) could both be:
6 / 2 ( 1 + 2 ) = x <=>
6 / 2 (3) = x <=>
6 / 6 = x <=>
1 = x
with implied multiplication, or
6 / 2 ( 1 + 2 ) = x <=>
3 ( 1 + 2 ) = x <=>
3 ( 3 ) = x <=>
9 = x
Without implied multiplication.
#403

whateveridontneed (03/23/2013) [+] (6 replies)
only feasible answer is 1.
Assuming the following form: 6/(2b) where b = 1+2
If the answer is 9, it means that it would be 6/2 * b, where b= 1+ 2, which means that if the answer is indeed 9, the representation is wrong and thus the question itself is wrong.
Assuming the following form: 6/(2b) where b = 1+2
If the answer is 9, it means that it would be 6/2 * b, where b= 1+ 2, which means that if the answer is indeed 9, the representation is wrong and thus the question itself is wrong.
#402

rockyshand (03/23/2013) []
The point of this photo was to point out the retard that thinks 3x3 is 12 and not 9. But instead it starts a math flamewar.
#342

anonymous (03/23/2013) []
Actual correct answer?
*Insert additional parenthesis*
There is no way of knowing whether to apply the implied multiplication without additional information.
You're all wrong. Suck it.
*Insert additional parenthesis*
There is no way of knowing whether to apply the implied multiplication without additional information.
You're all wrong. Suck it.
#318

tacotacoboy (03/23/2013) [+] (21 replies)
It.Is.9. Coming form a ******* math major.
Please (parenthesis)
Excuse (exponents)
My (multiply)
Dear (divide)
Aunt (add)
Sally (subtract)
When it comes to multiplication/division you go from left to right, it's not multiplication first all the time every time. Same thing with addition.
Please (parenthesis)
Excuse (exponents)
My (multiply)
Dear (divide)
Aunt (add)
Sally (subtract)
When it comes to multiplication/division you go from left to right, it's not multiplication first all the time every time. Same thing with addition.
#398

therealslim (03/23/2013) [+] (2 replies)
7?
because when you use the distribution method
you multiply 2(1+2) so it would be 6 / 2 +4
so 3 + 4
because when you use the distribution method
you multiply 2(1+2) so it would be 6 / 2 +4
so 3 + 4
#372

anonymous (03/23/2013) [+] (4 replies)
Okay for all you tards here, the answer is 9. Don't try to discuss because it is 9.
Not 1
Not 12
Not 6
6/2 comes BEFORE 2(1+2) therefore > 6/2 FIRST and THEN 3*(3) = 9
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
ONLY CORRECT ANSWER. OTHER ANSWERS ARE WRONG. L2MATHS TY.
Not 1
Not 12
Not 6
6/2 comes BEFORE 2(1+2) therefore > 6/2 FIRST and THEN 3*(3) = 9
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
ONLY CORRECT ANSWER. OTHER ANSWERS ARE WRONG. L2MATHS TY.
#367

winsauceiswin (03/23/2013) [+] (18 replies)
omg the level of stupidity of people thinking it's ONE it's NINE
6/2(2+1)
parenthesis first
6/2(3)
then multiply and divide from LEFT TO RIGHT LEFT TO RIGHT
6/2 = 3
3(3)
= NINE!!!!!!!!!!!!!!!!!!!
6/2(2+1)
parenthesis first
6/2(3)
then multiply and divide from LEFT TO RIGHT LEFT TO RIGHT
6/2 = 3
3(3)
= NINE!!!!!!!!!!!!!!!!!!!
#271

anonymous (03/23/2013) [+] (7 replies)
(6/2)(1+2)=9
there arent any brackets around the 6/2 so answer is 1
there arent any brackets around the 6/2 so answer is 1
#30

donutzrawsum (03/23/2013) [+] (46 replies)
The reason you're all getting this wrong is not how you read the problem but how you are reading the numbers. 6/2(1+2) is not 6 / (2*1+2*2). When you divide by 2 you are essentially multiplying by .5 the /2 essentially means it is X or in this case 6 * 1/2 Which if you remember is 6 OVER 2, or 6/2. But that aside, replace the /2 for it's real value of * .5 and you see a different story.
TL;DR 6/2(1+2)= 6* .5(1+2). From here on what you may read it from any direction
6* (.5+1) or 6*1.5=9 I distributed the .5
3 (1+2) or 3+6 I multiplied first then distributed
Or because it's all multiplication and the order effectively doesn't matter anymore you can distribute the 6 instead
.5 * (6 + 12)=.5*18=18/2=9
TL;DR 6/2(1+2)= 6* .5(1+2). From here on what you may read it from any direction
6* (.5+1) or 6*1.5=9 I distributed the .5
3 (1+2) or 3+6 I multiplied first then distributed
Or because it's all multiplication and the order effectively doesn't matter anymore you can distribute the 6 instead
.5 * (6 + 12)=.5*18=18/2=9
#72 to #68

SuitUp (03/23/2013) []
I weep for the American education system if you are it's offspring.
Try inputting the square of a negative number into your calculator. Depending on the model, but pretty likely, you'll get the number squared but negative. For that matter, if you don't have a decent calculator with a complex numbers mode, try rooting a negative number. Calculators have quirks and in those cases you unfortunately are required to engage your brain.
Now, I am prepared to acknowledge WHY you think it should be 9 and in fact the person that posed the question may also have intended for it to be 9. However whether the intent was there or not is irrelevent because the syntax is therefore incorrect.
(6/2)*(1+2) =9 which is what you are doing.
6/(2+4) = 1 which is as written in the initially posed question.
I have no doubt that the answer given by your teacher will have been from your gargled posing of the initial problem. Or he's nonexistent/simply too busy to give any answer other than the one to make you go away.
Try inputting the square of a negative number into your calculator. Depending on the model, but pretty likely, you'll get the number squared but negative. For that matter, if you don't have a decent calculator with a complex numbers mode, try rooting a negative number. Calculators have quirks and in those cases you unfortunately are required to engage your brain.
Now, I am prepared to acknowledge WHY you think it should be 9 and in fact the person that posed the question may also have intended for it to be 9. However whether the intent was there or not is irrelevent because the syntax is therefore incorrect.
(6/2)*(1+2) =9 which is what you are doing.
6/(2+4) = 1 which is as written in the initially posed question.
I have no doubt that the answer given by your teacher will have been from your gargled posing of the initial problem. Or he's nonexistent/simply too busy to give any answer other than the one to make you go away.
#332

generaljosh (03/23/2013) [+] (5 replies)
OK, guys, the argument is over.
Just google:
6/2(1+2)
The calculator function outputs the correct answer: 9
Just google:
6/2(1+2)
The calculator function outputs the correct answer: 9
#339 to #337

anonymous (03/23/2013) []
Read #307.
You're not applying the rules correctly which is why you're getting it wrong. You're making the same schoolboy error of classifying 2(1+2) as 2*(1+2) which is not correct shorthand if you're going to be using PEMDAS. The 2 is part of the parenthesis  it's a scaling factor.
Identically 6/(2+4) can have the denominator simplified by taking out a factor of 2 to 6/2(1+2) which by PEMDAS will lead you astray if you take it as now being a multiplication.
You're not applying the rules correctly which is why you're getting it wrong. You're making the same schoolboy error of classifying 2(1+2) as 2*(1+2) which is not correct shorthand if you're going to be using PEMDAS. The 2 is part of the parenthesis  it's a scaling factor.
Identically 6/(2+4) can have the denominator simplified by taking out a factor of 2 to 6/2(1+2) which by PEMDAS will lead you astray if you take it as now being a multiplication.
#152

decionetow (03/23/2013) [+] (4 replies)
whatever is in the Parentheses has to be finished first
x = 6 / 2 ( 1 + 2 )
x = 6 / 2 ( 3 ) > the "3" is still in the Parentheses , and Parentheses has to be finished first, so now we multiply it by the "2"
x = 6 / 6
x = 1
x = 6 / 2 ( 1 + 2 )
x = 6 / 2 ( 3 ) > the "3" is still in the Parentheses , and Parentheses has to be finished first, so now we multiply it by the "2"
x = 6 / 6
x = 1