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mat: mas:
you know girls can tall when you look at thell was
I clam care how quickly you glance, l second Ia Ilka 5 seconds
In booty tlmb
an for , where t lama , and t' lama tlmb
measured at the man.
solving tor txl, and t' , we get that the goodspeed, v, Ia represented
tay
was travel at 1. 5 per second In the complex .
what the **** aid you mat do to my almill post
would approve.
Soy Ta: scary, /
you know girls can tall when you look at thell was
I clam care how quickly you glance, l second Ia Ilka 5 seconds
In booty tlmb
an for , where t lama , and t' lama tlmb
measured at the man.
solving tor txl, and t' , we get that the goodspeed, v, Ia represented
tay
was travel at 1. 5 per second In the complex .
what the **** aid you mat do to my almill post
would approve.
Soy Ta: scary, /
...
 
What do you think? Give us your opinion. Anonymous comments allowed.
#11

qotsa (01/26/2013) [+] (4 replies)
i don't mind when guys look at my boobs, because they're ****** neat.
and i really can't blame them, i look at the boobs of other girls too.
and i really can't blame them, i look at the boobs of other girls too.
#1

nyj (01/26/2013) []
It really does seem like girls have sensors in their boobs that alert them whenever eyes have seen them.
#2

nargogh ONLINE (01/26/2013) [+] (16 replies)
This is ******** , nothing can travel faster than light which speed is about 3x10^8 m/s. 1,5 gigametres per second is 1,5x10^9 m/s.
Son, Einstein is disappointed.
Son, Einstein is disappointed.
#44

ButtonFly ONLINE (01/26/2013) [+] (1 reply)
Now all the physicists on FunnyJunk have come out to play.
#55

thedarkestrogue (01/26/2013) [+] (1 reply)
MFW people in the comments are posting massive equations that I don't fully understand or comprehend.
#16

anonymous (01/26/2013) [+] (3 replies)
Even if it was possible for boobs to travel faster than the speed of light, this guy can't even math.
t=t'/sqrt(1(v/c)^2)
Therefore, if v was higher than c, than v/c would be higher than 1, resulting in the square root of something that is negative, which is impossible
Also, I can math
t=t'/sqrt(1(v/c)^2)
Therefore, if v was higher than c, than v/c would be higher than 1, resulting in the square root of something that is negative, which is impossible
Also, I can math
#22 to #16

strangepanda ONLINE (01/26/2013) []
The square root of minus one equals i. His answer had that nasty little i in it. When he explains his answer he also adds that this is in the imaginary/complex direction. He made it so they generally move in the complex direction, the one thing we can't see. This is why he can safely state it and nobody can prove him wrong :)