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Back to the content 'Stephen Fry and Lady Gaga meet for tea.'
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> hey anon, wanna give your opinion?
asd
2
new threads.
1
new replies.
#285

pandasecret
Reply
+1
123456789123345869
(01/09/2013)
[]
**pandasecret rolls 3,589**
The chance of me getting quads is 1/1111
#290
to #285

anon
id:
5db3e5a8
Reply
0
123456789123345869
(01/09/2013)
[]
Isn't it 1/1000?
#295
to #290

psykobear
Reply
+3
123456789123345869
(01/09/2013)
[]
There are 10,000 possible numbers, since 10^4 is 10,000.
10 possible quads
10/10,000 > 1/1,000
Anon wins!
#315
to #295

pandasecret
Reply
+1
123456789123345869
(01/10/2013)
[]
I didn't include 0000. I only calculated for 1111, 2222, etc... 8888, 9999. 0000 does not qualify as a quad for me
#318
to #315

psykobear
Reply
+1
123456789123345869
(01/10/2013)
[]
Ok then, if you don't count 0000, then 9/10,000
#327
to #318

pandasecret
Reply
+1
123456789123345869
(01/10/2013)
[]
no, because the number set would have been 1111,2222,...,9999 (nine numbers) and the whole set 0001,0002,9999 (including quads, 9,999 numbers, exculding quads, 9,990 numbers) So we were both wrong. It was 9/9990 or 1/1110.
#330
to #327

psykobear
Reply
0
123456789123345869
(01/10/2013)
[]
Actually, the wholes set is 10,000 numbers because you are excluding 0000 from the set, even though it could be rolled.
# of 1 digit numbers (09):10 or 10^1 or 10
# of 2 digit numbers (0099):100 or 10^2 or 10*10
# of 3 digit numbers (000999):1,000 or 10^3 or 10*10*10
# of 4 digit numbers (00009999):10,000 or 10^4 or 10*10*10*10
#331
to #330

psykobear
Reply
0
123456789123345869
(01/10/2013)
[]
Or, thanks to probability, you could think of it as this:
Possible outcomes for the 1st digit:10 (09)
Possible outcomes for the 2nd digit:10 (09)
Possible outcomes for the 3rd digit:10 (09)
Possible outcomes for the 4th digit:10 (09)
Multiply the possible outcomes: 10 * 10 * 10 * 10 = 10,000 (00009999)
#333
to #331

psykobear
Reply
0
123456789123345869
(01/10/2013)
[]
Now, we know for sure that there are 10,000 possible outcomes. When finding the probability of selecting one at random, you put the number of outcomes you want over the number of total possible outcomes.
If you count 0000 as a quad:_______________________________________
Wanted outcomes(quads, including 0000):10 (0000, 1111, 2222, etc.)
Total possible outcomes:10,000 (0000, 0001, 0002, etc.)
Chance of rolling quads (including 0000):10/10,000 or 1/1000 0r .001
If you DON'T count 0000 as a quad:_________________________________
Wanted outcomes(quads, except 0000):9 (1111, 2222, 3333, etc.)
Total possible outcomes(doesn't change):10,000 (0000, 0001, 0002, etc.)
Chance of rolling quads (excluding 0000):9/10,000 or .0009
#334
to #333

psykobear
Reply
0
123456789123345869
(01/10/2013)
[]
Sorry for all the math, but I like explaining this stuff to people.
#332
to #331

psykobear
0
123456789123345869
has deleted their comment
[]
#329
to #327

flyingfrogslash
0
123456789123345869
has deleted their comment
[]
#319
to #318

psykobear
Reply
+1
123456789123345869
(01/10/2013)
[]
**psykobear rolls 5,491**
#320
to #319

psykobear
Reply
+1
123456789123345869
(01/10/2013)
[]
Thought I would give it a shot :p
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