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How to Math
By: boonghillie
Tags: fc
90% of math
graduates can' t
solve this equation
graduates can' t
solve this equation
...
 
What do you think? Give us your opinion. Anonymous comments allowed.
#28

simeonc (01/04/2013) [+] (10 replies)
Rearrange
Y = Y + 2
Programmers thinking:
2, 4, 6, 8 etc
problem?
Y = Y + 2
Programmers thinking:
2, 4, 6, 8 etc
problem?
#114

anonymous (01/04/2013) [+] (2 replies)
I don't consider myself all that great at math, but the sheer level of retardedness in the comments is astounding.
#13

Daeiros ONLINE (01/04/2013) [+] (1 reply)
its easy
y=i
i is an imaginary number that is both positive and negative at the same time used when taking the square root of a negative number(which is impossible otherwise, but the need comes up sometimes)
i + 2 = i
because it is simultaneously positive and negative, we can say
1 + 2 = 1
which is correct
y=i
i is an imaginary number that is both positive and negative at the same time used when taking the square root of a negative number(which is impossible otherwise, but the need comes up sometimes)
i + 2 = i
because it is simultaneously positive and negative, we can say
1 + 2 = 1
which is correct
#16 to #13

anonymous (01/04/2013) []
That's not how i works at all. You need to revisit math a little bit. It is the square root of 1, which you had correct, but it is neither negative nor positive. ( i+i is not the same as 1 + 1, nor 1 + 1, or 1  1. It is i + i, which is 2i. ) As such, no, you are incorrect. Zero credit. Good day, sir.
#195

thewalruss (01/05/2013) [+] (1 reply)
actually, Y = ∞...
∞ + 2 = ∞
By the way, that is not a infinity simbol... those are boobs.
∞ + 2 = ∞
By the way, that is not a infinity simbol... those are boobs.
#193

jamesrustler (01/05/2013) [+] (1 reply)
I read in the comments that it can't be solved because it's a meaningless equation.
God damn I wish I was smart enough to understand **** like this.
God damn I wish I was smart enough to understand **** like this.
#174

predalien (01/05/2013) []
**predalien rolled a random image posted in comment #17 at Racist Barn Racist Barn 1 2 3 4 ** mfw
#40

therianek (01/04/2013) [+] (5 replies)
Imo i would use derivation on this...
y+2=y
first derivation:
f(x) : y+2 = y
f(x)' : 1 = 1
because derivation from y is 1 and derivation from 2 is 0
Problem solved
y+2=y
first derivation:
f(x) : y+2 = y
f(x)' : 1 = 1
because derivation from y is 1 and derivation from 2 is 0
Problem solved
#47 to #40

quarklion (01/04/2013) []
Except that didn't really solve it, since you didn't even adress the equation itself.
You didn't even try to adress it as an equation. Equations are solved by finding the values of the variable(commonly x, but here it's y) for which both sides are equal.
Functions on the other hand is finding the output for different values of x.
An example of an equation is 2+x=2x with the solution being x=2. Equations can exist for which there is multiple solutions. An example is 1=x^2 with both x=1 and 1 being valid answers
An example of a function is f(x)=3x+7 with there being a different output for each value of x. Functions can exist where certain values of x is invalid. An example is f(x)=1/x with x=0 being invalid.
As a sidenote f(x) means function of x, so for your invalid attempt you should've written f(y).
Also my "attempt" at solving this.
y+2=y
2=yy
2=0
No valid answer.
You didn't even try to adress it as an equation. Equations are solved by finding the values of the variable(commonly x, but here it's y) for which both sides are equal.
Functions on the other hand is finding the output for different values of x.
An example of an equation is 2+x=2x with the solution being x=2. Equations can exist for which there is multiple solutions. An example is 1=x^2 with both x=1 and 1 being valid answers
An example of a function is f(x)=3x+7 with there being a different output for each value of x. Functions can exist where certain values of x is invalid. An example is f(x)=1/x with x=0 being invalid.
As a sidenote f(x) means function of x, so for your invalid attempt you should've written f(y).
Also my "attempt" at solving this.
y+2=y
2=yy
2=0
No valid answer.
#180

Kabutops (01/05/2013) []
uhm...there's no answer for the variable? (90% of gradautes my ass)
#19

ipmules (01/04/2013) [+] (3 replies)
Here we go. This goes for any of the commonly known sets of numbers in mathematics, namely the naturals, integers, rationals, reals and complex. For any element in the set (we'll call it x, and in this example we'll just deal with naturals,) there exists a unique solution to the equation x+a=x=a+x, meaning a is the identity element in respect to addition, or is the additive identity. In all of these sets, the additive identity is 0. That means that x+a=x=a+x is only true when a=0. Since this is a case where a=2, it can no longer hold true for any x in any of the above sets.
TL:DR: There exists no solution.
TL:DR: There exists no solution.