How to Math

no then we could do:

y - y = 2 as in ∞ - ∞ = 2 and all math is fucked

ah yes, good point.

what?
what i did is subtract y from both ends of the equation to make y-y=whatever
and when i did that i became infinity minus infinity equals 2 which is wrong which is why this mo fo has no solution

infinity minus infinity is in fact not 0, it can be anything you like, really.
lets say ∞ +2 = ∞, which is true
> ∞ - ∞ = 2
> 2*(∞ - ∞) = 2*(2)
> ∞ - ∞ = 4
therefore we can also say that infinity minus infinity equals infinity. because infinity plus infinity is still infinity. Its an irrational number.

nope check my comment below for the answer

I don't understand what you mean.

There's nothing here to learn, just gibbering and a somewhat clever dick joke.

im not serious, i said that because i actually wasn't learn math on the internet, just nonsense math, my use of reverse sarcasm was displaying my false stupidity, hence with the hoped result of creating laughter. Its quite complex humor really, im not surprised you are baffled.

Your lame undertaking to confound me is evidence enough that you are not as of yet fully aware of my country of origin.
I am an Englishman, you see.
While the plashet of melatonin that once was known as my cerebrum has indeed been encumbered with your nebula of deceit, I see now the ironic sarcasm in your statement and stand up fully to accept the extent of my deserved ignominy.

My affluence of intellect has been stripped from me and I am left indigent of cerebral power in your eyes.
I only hope my considerable essay at making my vocabulary as eclectic as your own will make up for my shortcoming.

I extol your innovative use of ironic sarcasm, and I bid you good day.

I too am a brit, and thank you for such a timely response, i admire the flair in your writing.
That second statement was also a joke, due too my humorous and clearly false explanation. I hope you had a jolly good laugh.
I am quite the punster today.
Good day.

Aha, I see your deceit for what it is you charlatan!

For I too, am an Englishman!

No longer does the veil remain opaque in such stark contract to the translucent axiomatic light of truth. The nature of your disposition is now laid upon the alter for all to see!

Your flimflam foolery is a shambles, good sir. The tempered spear of transcendent observation reveals that you are, indeed, a Frenchie!

That white behind yourself there, it is of the colour of a coward! Thine soul rest with the garlic munchers!

I had to join in.

hey notsixroller, this is songofstorms new account, i know you fellow brit!

'AIGHT M8!

HOW YA DOIN'?!

Im fakin good m8.
just 'ad a blady wank.

where in angleterre do you live?

IOW

What happens there, stays there. Which happens to be not much, so you probably wouldn't care to tell anyone. :3

SO LUCKKYYYY.
i want to live there, im from the shitole of england, London..

I will admit I don't like cities, but London does have a charm.

What about it do you like?

what do you like about IOW

id love to live in newport mate.

LOL nothing.
it has some nice shops. Its a melting pot of humans from all cultures, ( yet a few white people still look at me and immediatly cross the road, then cross again when i turn around to look).

thats about it.
london is so overrated.
I just realised IOW is a quarter of the size of london alone.. thats fucking awesome.

I do like the place.

Anyway, I'm going to watch Hannibal, so I'll so you around. :3

speak soon m8 :3

I did have such an inkling, it is good to see!
And I thank you most profoundly for your complements.

Pfffffffffffffffffenough.
Y'right m8?
Nice jokes, and yeh I did catch the second one, but as I said (if you caught it, something to do with melatonin) I'm pretty fuckin' shattered and not up to much more.
'Ave a good one! ^^

yeah ate, 15 past 11, im fakin knackered, but ive got a metal gear solid 2 too play, so yeah.
anyway, sleep well bruv, take care.

Hah, 'n' you, when you nod off.
Nighty.

unlucky brah, at least you tried.

Well, infinity = infinity + 2.

No.

Are you really really sure about that? Would you please provide proof for that statement? You know, even an infinity + an infinity = an infinity. And then there are infinities of different sizes as well. For instance, an infinity made of all rational numbers is smaller than an infinity made of all irrational numbers, but all infinities composed only of rational numbers are equally big. Therefore, an infinity + 2 (rational) = an infinity.

but if we change your equation to the following: "2 = an infinity - an infinity"
so, no matter what these infinitys are they both have to be the same and therefore if you subtract them you'll get 0 and then the equation is "2 = 0" which isn't true so the answer is that there is no solution.

Actually, it would be (2 + an infinity) - an infinity = 0, which is completely correct.

Infinity is the concept that a number is growing larger, so infinity/2 or infinity*2 or infinity+25 or infinity-1351321698654 are still equal to infinity. But nowhere in the original equation do we ever talk about infinity...

Y += 2;

Would be much more efficient though..

this only applies if there's a loop, otherwise its just 2

main()
{

char subject;
cin >> subject;

if (subject = "programming") {
cout << "Good work soldier!" << endl;
}
else {
cout << "Keep your filthy programming out of this, it ain't relevant." << endl;
}
return 0;
}

I'll take that and raise it up a bit:

typedef struct subjectlist
{ char letter;
subjectlist *next; }

int main ()
{ const char subject = "programming";
subjectlist *compare;
subjectlist *root;


dglfdlfd af
df l;gl slh p
fa df;a' df
a a;g ds;h;gd#s;h gfsh tsyoh kos[rth s
fd'glfsd

dfdajpfijadpi gjpsg pdksogh

return -1;}

I would advise against compiling this code though.

Oh god what the fuck x3

I just learned a bit of code as a personal project once, I have no idea what any of the sensical things there mean, let alone the (I presume) nonsensical parts.

In order to fully understand the complexity of linked lists you will have to compile and run (multiple times if needed) the following code:

do {beer;}
while (sober);

And then I realised do-while was a loop.

Well I'll be killing myself now.

You could have just looped it, but it's understandable you didn't want to take the effort x3

And just, for clarification.
Do action "beer" (to drink a beer) while "sober = 1" (1 being true) right?

Yes. Usually loops require something to be transformed into a boolean value {0,1}. When sober=0, the program may chose to stop looping "beer". Though it doesn't work for all compilers that way. Some end up in an alcoholic coma in hospital.

Nicely put, 10/10

And the content. 100% of people can't solve that equation.

That's because there is no solution...

y is a variable taking place of a number

you know in order to properly do this you separate it into left side and right side that way at no point will you have anything equal to something it isn't.
essentially:

LS. | RS.
y+2 | y

therefor LS =/= RS
Q.E.D.

At least in his method he put that y = 2/0 which is the next most correct answer.

"LS =/= RS"

but... the left side does equal the right side... that's how equations work

so youre telling me y+2 = y, that the right side IS equal to the left? which isn't actually possible except in the imaginary (so in this context its not possible because we're working as elements of the real number system)

y+2=/=y
y+2=y+2

ah shit... I accidentally the whole thing...

forgive me, my brain went to mush, I thought you just meant in a proper equation, the left side does not equal the right side. I didn't know you meant this specifically and forgot that when solving things algebraically you do separate the sides.

its okay, happens to the best of us.

if we can always work in the imaginary numbers when discussing LS and RS then in theory every left side is equal to every right side.

I am a math major, but haven't graduated yet and I believe that any of my fellow scholars would have no trouble coming to the same conclusion.

what about derivation? it might work...

It's a common fallacy in differential equations that a solution to the derivative implies a solution to the original equations. Such is not the case. Think about f(x)=x^2+3 and g(x)=x^2+5. f `(x) and g `(x) are equal, but f(x) =/= g(x). There are cases in which y=y+2 does yield a solution, but only when 0=2. One example of this is under modulo arithmetic, namely (z mod 2.) In this case, y is congruent to y+2, but as modulo arithmetic is an arithmetic on the integers, you only have integer solutions. Typically when people are discussing problems like these, the assumption is that we're working under elementary arithmetic in the reals.