Simple math

wait...lolwat. 3 times the square root of 81=81 divided by 3?

The question is asking what the equation approaches as x gets closer to the limit but not what it is AT the limit. so in both it would be +- infinity because you are dividing over a number that is infinitely small in + or - depending on what direction you approach from. [url deleted]
is a graph of both of these questions (not really but it shows the idea)

This is why schools should just use standard limit notation. (parentheses) for approaches without bound, and [brackets] for reaches. so this would be (-∞,5) (5,∞) because the function never has an X value of negitive infinity, 5, or positive infinity.

in the first one it is asking for a limit (lim) or the value of y as x approaches 8. The close you get to 8 (8.0001 for instance), the smaller the number you are dividing by, which inscreases the number you are dividing. so when you get really really small like .00000000000001 it approaches infinity.

for the second one it is asking about the value of y as the line of the second equation's graph approaches 5 on the x axis. The close you get to 5, the smaller the denominator becomes and the lager the numerator becomes after division; the limit is infinity again.

the joke is based on the two upright 8's and the "sideways 8" (infinity sign) in the first one and there being 5 upright 5's in the second so someone put a sideways 5 as the answer

That is correct. As there is no indication of direction it is asking for the overall limit, which does not exist. It does not exist because the limit from the left and the limit from the right are different. In order for the statement to be correct it should specify that they are taking the limit from the right.

the limit of the exuation 1/(x-8) as x approaches the value 8 is infinity. Reason being is that as x approaches 8 the equation becomes closer 1/0. 1/0 is infinity kinda. Same goes for 5.

**anonymous rolls 3,378** by quads anon out

Just to point this out, but by your logic, 0 isn't a number either.
1*0=0
2*0=0
1=2
yeah, doesn't work.

So the limits don't exist? Are you stupid or do you have another problem?