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Paradox?
Uploaded by: dishesaredone
If you choose an answer to this question
at random, what is the chance you will be correct
at random, what is the chance you will be correct
...
| |
I haven't seen anyone get this right.
0% is not an option. You can't pick it.
the options are:
25% which is wrong because there is a 50% chance of picking it.
50% which is wrong because there is a 25% chance of picking it.
60% which is wrong because there is a 25% chance of picking it.
None of the answers are correct. The question therefore, is inherently flawed.
0% is not an option. You can't pick it.
the options are:
25% which is wrong because there is a 50% chance of picking it.
50% which is wrong because there is a 25% chance of picking it.
60% which is wrong because there is a 25% chance of picking it.
None of the answers are correct. The question therefore, is inherently flawed.
#178
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N. Korean citizen (09/02/2012) [+]
(7 replies)
First, the task is to answer the question at random. You have 4 oppotunities that is 25% chance to be correct.
Second we observe that A and D are the same (25%) That leaves us with 3 possibol answers.
A-D 25%
B 50%
C 60%
When ever you have 3 oppotunities you have a 33,33% chance to be correct.
But the paradox is that the answer changes each time you choose an anser for exampel if you choose 60% you are 25% likely to be right. If you choose 25% you are 50% likely to be correct.
And it's impossibol to pick random when you allready have seen the numbers.
Second we observe that A and D are the same (25%) That leaves us with 3 possibol answers.
A-D 25%
B 50%
C 60%
When ever you have 3 oppotunities you have a 33,33% chance to be correct.
But the paradox is that the answer changes each time you choose an anser for exampel if you choose 60% you are 25% likely to be right. If you choose 25% you are 50% likely to be correct.
And it's impossibol to pick random when you allready have seen the numbers.
#28
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N. Korean citizen (09/02/2012) [+]
(2 replies)
There are 4 choices. The answer is either A, B, C, or D, so the chances of you picking the correct one regardless of its answer is 25%.
you're all looking at it wrong, it would be 25% but then there are two so it would be 50% but there is one so it would be 25% etc.. etc.. etc.. he never said "chose an answer at random what where your chances of getting it right" he said "IF" which means you do not have to choose the answer at random
TL;DR you don't have to choose a random answer that has nothing to do with it.
TL;DR you don't have to choose a random answer that has nothing to do with it.
#101
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N. Korean citizen (09/02/2012) [-]
addictakilla helped me on this, but im gonna explain it better
ignore the fact that answers are percents
If you choose a random answer, what is the %?
A. Red
B. Red
C. Blue
D. Green
If i picked randomly, there is a 50% chance of me picking red, 25 of blue and 25 of green. Now if you replace red blue and green with 25 50 and 60, the answer is still 50%. the fact that option B is 50 has no meaning.
"dont judge by the content of each answer, just the quantity of the total answers."
-addictakilla
ignore the fact that answers are percents
If you choose a random answer, what is the %?
A. Red
B. Red
C. Blue
D. Green
If i picked randomly, there is a 50% chance of me picking red, 25 of blue and 25 of green. Now if you replace red blue and green with 25 50 and 60, the answer is still 50%. the fact that option B is 50 has no meaning.
"dont judge by the content of each answer, just the quantity of the total answers."
-addictakilla
#122
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N. Korean citizen (09/02/2012) [-]
everyone is incorrect it is c. 60 %
because it works everytime
because it works everytime
Okay, this always pisses me off, let me break it down for you.
They whole point of this is picking an answer at random, but being correct.
You have 4 options, thus a 25% chance of picking any option.
Two of the answers are the same. Ignoring the math basis of the question, that being the odds of being correct, then you know 2/4 of them are either right or wrong.
With the two that are the same, you have a 50% chance of them being correct or incorrect. But either way you have a 50% chance of picking them.
Thus, we have a 50% chance of being correct. It's B. With the question proposed, the answer is B
They whole point of this is picking an answer at random, but being correct.
You have 4 options, thus a 25% chance of picking any option.
Two of the answers are the same. Ignoring the math basis of the question, that being the odds of being correct, then you know 2/4 of them are either right or wrong.
With the two that are the same, you have a 50% chance of them being correct or incorrect. But either way you have a 50% chance of picking them.
Thus, we have a 50% chance of being correct. It's B. With the question proposed, the answer is B
If we assume that this is a standard multiple choice question, in which our options to select between are A, B, C, and D, then the odds of picking each answer are as follows:
50% chance of picking A or D (25%)
25% chance of picking B (50%)
25% chance of picking C (60%)
So, it's clear that none of the answers are correct. 25% can't be the right answer, since there's a 50% chance of picking it. Similarly, 50% can't be the right answer, since there's a 25% chance of picking it. And 60% isn't even superficially plausible.
Therefore, the chance that you'll be correct is 0%.
50% chance of picking A or D (25%)
25% chance of picking B (50%)
25% chance of picking C (60%)
So, it's clear that none of the answers are correct. 25% can't be the right answer, since there's a 50% chance of picking it. Similarly, 50% can't be the right answer, since there's a 25% chance of picking it. And 60% isn't even superficially plausible.
Therefore, the chance that you'll be correct is 0%.
#184
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rollforthelol **User deleted account** (09/02/2012) [-]
**rollforthelol rolled a random image posted in comment #63 at Pizza ** /B/ is always the answer