Home  RSS Feeds 
Original Content  
Funny Pictures  Funny Videos 
Funny GIFs  YouTube Videos 
Text/Links  Channels 
User Rankings  
NSFW Content 
What do you think? Give us your opinion. Anonymous comments allowed.
#171 to #145

anonymous (03/07/2012) []
**anonymous rolled a random image posted in comment #1 at Bronies **
I thumbed up OP's pic not because i liked it, but so that your comment gets more exposure. truly an epic roll. i applaud you
I thumbed up OP's pic not because i liked it, but so that your comment gets more exposure. truly an epic roll. i applaud you
#221 to #166

fignewtonz (03/07/2012) []
the chances of 2 consecutive 888 rolls is 1/1,000,000, but the chances of rolling any trips and then someone else rolling the same trips is actually 1/100,000.
1 in 100 for the trips times 1 in 1000 for the repeat. it's still ******* impressive, same odds as getting all the same digits on *roll 6*, but not 1/1,000,000
Math is fun, kids!
1 in 100 for the trips times 1 in 1000 for the repeat. it's still ******* impressive, same odds as getting all the same digits on *roll 6*, but not 1/1,000,000
Math is fun, kids!
#451 to #221

Fgner (03/07/2012) []
OH WAIT I SEE WHERE YOU WENT WRONG. Triples is 1/(10^3) which is 1,000 not 100! Then if the second roll was more rare, it would be 1/(10^4) which would be 10,000 and it would be 1/10,000,000 in total! But I'm pretty sure that two people rolling 3 and getting the same number for each 6 digits out of 10 possible digits would be (possibles ^ digits) = (10^6)....
#455 to #451

fignewtonz (03/07/2012) []
no, the probability of ANY triples is 1/1000. There are 1000 possible outcomes when you roll 3, right? out of those 1000, 10 are trips: 000, 111, 222, 333, 444, 555, 666, 777, 888, 999. 10 possible favorable outcomes out of 1000 total outcomes. 10/1000= 1/100. Then, to get the same trips, there is only 1 possible favorable outcome, so it is 1/1000. multiply those and you get 1/100,000
#449 to #221

Fgner (03/07/2012) []
I don't understand how that math works... Just because somebody else rolls, doesn't make it more likely by (n1) exponents? It's exactly the same chance of *roll 6* being... which is 10^6. Right? Excuse me, I haven't had to use this math in so long and I had to use a simple calculator with no exponents so I might have counted wrong to...
#149 to #147

beefking (03/07/2012) []
**beefking rolled a random image posted in comment #2813559 at FJ Pony Thread ** Finally, I have found my FJ brethren.