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The Dark Equation
Found this trolling the interwebz
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Batman Equador
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What do you think? Give us your opinion. Anonymous comments allowed.
#15

partywagon (02/28/2012) [+] (3 replies)
funnyjunk.com/funny_picture... posted this months ago, 16 thumbs :(
#27

xcmxcmx (02/28/2012) [+] (3 replies)
this could be complete ******** and nobody would ever know.
#37

obliquezombie (02/28/2012) [+] (6 replies)
"I found this trolling the interwebz."
Trolling. You keep saying this word, and I do not think you know what it means.
Trolling. You keep saying this word, and I do not think you know what it means.
#19

gerthc (02/28/2012) [+] (1 reply)
2 sqrt(abs(abs(x)1)*abs(3abs(x))/((abs(x)1)*(3abs(x))))(1+abs(abs(x)3)/(abs( x)3))sqrt(1(x/7)^2)+(5+0.97(abs(x.5)+abs(x+.5))3(abs(x.75)+abs(x+.75)))(1+a bs(1abs(x))/(1abs(x))),3sqrt(1(x/7)^2)sqrt(abs(abs(x)4)/(abs(x)4)),abs(x/2 )0.0913722(x^2)3+sqrt(1(abs(abs(x)2)1)^2),(2.71052+(1.5.5abs(x))1.35526sq rt(4(abs(x)1)^2))sqrt(abs(abs(x)1)/(abs(x)1))+0.9
Simply type this in google search bar...
Simply type this in google search bar...
#5

feragon (02/27/2012) [+] (1 reply)
I very much doubt that this is possible without having assymptotes/limits