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> hey anon, wanna give your opinion?
asd
#11 to #6

finishhimlarry
Reply +20 123456789123345869
(09/15/2012) [] *insert obligatory "YEEEEEEEEEEEEEEEAAAAAAAAHHHHHH" picture here*
#111

gratrunka
Reply +100 123456789123345869
(09/16/2012) [] Okay, lets get some Math up in this bitch
The formula for Centripetal Acceleration, the speed the train needs to be at the top of the circle, is A=Speed2 / Radius of the circle.
Okay, so since the diameter of the circle is roughly the length of the train, and the train has 4 carriages, then it's Train Carriage x 4. Now, the average train carriage is 75 foot long, so thats 75ft x 4, which is 300ft. Diameter of Circle is 300ft, so radius is 150ft. Have our radius in feet. Since the sum is in Meters, we convert it to 45.72 meters. Theres our radius
We know that A at the pinnacle of the circle is 9.81 m/s2 so thats settled.
To Find the speed necessary to do the loop de loop, we have to mess with the equation a bit.
a= V2 / R
V2 = A x R
V = Square Root (AxR)
Now just add in the numbers
V = SR (9.81 m/s x 45.72)
I'll skipp the calculations and just tell you that the answer is 21.178 meters be second.
Convert that into Kilometers per hour =
63.53 kilometers per hour. So this **** is possible.
Let's call Mythbusters
The formula for Centripetal Acceleration, the speed the train needs to be at the top of the circle, is A=Speed2 / Radius of the circle.
Okay, so since the diameter of the circle is roughly the length of the train, and the train has 4 carriages, then it's Train Carriage x 4. Now, the average train carriage is 75 foot long, so thats 75ft x 4, which is 300ft. Diameter of Circle is 300ft, so radius is 150ft. Have our radius in feet. Since the sum is in Meters, we convert it to 45.72 meters. Theres our radius
We know that A at the pinnacle of the circle is 9.81 m/s2 so thats settled.
To Find the speed necessary to do the loop de loop, we have to mess with the equation a bit.
a= V2 / R
V2 = A x R
V = Square Root (AxR)
Now just add in the numbers
V = SR (9.81 m/s x 45.72)
I'll skipp the calculations and just tell you that the answer is 21.178 meters be second.
Convert that into Kilometers per hour =
63.53 kilometers per hour. So this **** is possible.
Let's call Mythbusters
#118 to #111

snarfalupticus
Reply 0 123456789123345869
(09/16/2012) [] its from a french commercial.
#120 to #111

WakaTakaBang
Reply 0 123456789123345869
(09/16/2012) [] Why would you think that the centripetal acceleration at the pinnacle is 9.81 m/s2?
#125 to #120

kaelanduck
Reply +1 123456789123345869
(09/16/2012) [] It has to be at least that or gravity will have it's way
#252 to #125

WakaTakaBang
Reply 0 123456789123345869
(09/16/2012) [] I know why it has to be at least it, but why does it have to be? Isn't it possible it could be going faster?
#155 to #111

ifiwereayoungman
Reply 0 123456789123345869
(09/16/2012) [] Did you take mass into account in that equation? I'm sure that would make a bit of a difference.
#170 to #111

anon id: afecc40e
Reply 0 123456789123345869
(09/16/2012) [] You forgot to take into account the fact that this is not uniform circular motion. The train will loose its kinetic energy as it climbs the loop.
Also, your method of estimating the radius of the circle is very poor. In the gif, it did not show the length of the train compared to the loop, therefore for all we know, the train could be much longer or much shorter than the diameter of the loop.
Also, your method of estimating the radius of the circle is very poor. In the gif, it did not show the length of the train compared to the loop, therefore for all we know, the train could be much longer or much shorter than the diameter of the loop.
#196 to #111

OminousDemon
Reply 0 123456789123345869
(09/16/2012) [] i feel like it would need to be faster than 40mph :
#197 to #111

buttinspecter
Reply 0 123456789123345869
(09/16/2012) [] Wow. I just got done with my first engineering physics course. I didn't think I'd find a valid application so soon. Well, see you guys. I'm gonna go live the rest of my life without finding a single other application.
Seriously, I probably won't.
Seriously, I probably won't.
#265 to #111

penguinthegreat
Reply 0 123456789123345869
(09/16/2012) [] but there is a problem
the construction would fall apart
the construction would fall apart
#134 to #113

malevolentspoon
Reply +1 123456789123345869
(09/16/2012) [] Also to make sure the tops of the train cars don't get crunched together like soda cans while they're being pushed up against each other.
#212

zonryu
Reply +43 123456789123345869
(09/16/2012) [] **zonryu rolled a random image posted in comment #15 at 2 Hamsters 1 Wheel ** MFW
#138 to #18

ariachnotred
Reply 3 123456789123345869
(09/16/2012) [] See comment 111, will c/p for ease
Okay, lets get some Math up in this bitch
The formula for Centripetal Acceleration, the speed the train needs to be at the top of the circle, is A=Speed2 / Radius of the circle.
Okay, so since the diameter of the circle is roughly the length of the train, and the train has 4 carriages, then it's Train Carriage x 4. Now, the average train carriage is 75 foot long, so thats 75ft x 4, which is 300ft. Diameter of Circle is 300ft, so radius is 150ft. Have our radius in feet. Since the sum is in Meters, we convert it to 45.72 meters. Theres our radius
We know that A at the pinnacle of the circle is 9.81 m/s2 so thats settled.
To Find the speed necessary to do the loop de loop, we have to mess with the equation a bit.
a= V2 / R
V2 = A x R
V = Square Root (AxR)
Now just add in the numbers
V = SR (9.81 m/s x 45.72)
I'll skipp the calculations and just tell you that the answer is 21.178 meters be second.
Convert that into Kilometers per hour =
63.53 kilometers per hour. So this **** is possible.
Let's call Mythbusters
Okay, lets get some Math up in this bitch
The formula for Centripetal Acceleration, the speed the train needs to be at the top of the circle, is A=Speed2 / Radius of the circle.
Okay, so since the diameter of the circle is roughly the length of the train, and the train has 4 carriages, then it's Train Carriage x 4. Now, the average train carriage is 75 foot long, so thats 75ft x 4, which is 300ft. Diameter of Circle is 300ft, so radius is 150ft. Have our radius in feet. Since the sum is in Meters, we convert it to 45.72 meters. Theres our radius
We know that A at the pinnacle of the circle is 9.81 m/s2 so thats settled.
To Find the speed necessary to do the loop de loop, we have to mess with the equation a bit.
a= V2 / R
V2 = A x R
V = Square Root (AxR)
Now just add in the numbers
V = SR (9.81 m/s x 45.72)
I'll skipp the calculations and just tell you that the answer is 21.178 meters be second.
Convert that into Kilometers per hour =
63.53 kilometers per hour. So this **** is possible.
Let's call Mythbusters
#228 to #138

drastronomy
Reply 1 123456789123345869
(09/16/2012) [] *slow clap*
I am assuming it is correct. Too lazy to check it.
I am assuming it is correct. Too lazy to check it.
#288 to #228

ariachnotred
Reply 0 123456789123345869
(09/16/2012) [] Yay, four red thumbs haha
Funnyjunk logic at its finest
Funnyjunk logic at its finest
#49

jonashuelsman
Reply +21 123456789123345869
(09/16/2012) [] sometimes i masturbate with hotdogs
#87 to #51

DrSalvador
Reply +5 123456789123345869
(09/16/2012) [] Sometimes I put hotdogs in my anus
#121 to #87

threenewmessages
Reply +2 123456789123345869
(09/16/2012) [] I'm sweating like a homo holding some... hotdogs
#7

celestiasbeard
Reply +14 123456789123345869
(09/15/2012) [] "Sir won't that mess up our schedule for a while?"
"Do I look like I'm currently giving a ****?"
"Do I look like I'm currently giving a ****?"