when someone tries to explain math to me

x = f(u)cK (Y-0)/U

quadratic, looks like someone just got out of pre algebra

Nope were talking about surface area and volume right now.

Calculus itself is fairly easy. It's the really fucking insanely difficult algebra and trig that will eventually make calculus somewhat difficult at points.

I thought the u-substitution was horrible.

Wrong, should be written as
x = (-b ± √b² - 4(a)(c)) / 2(a), remember your order of operations people.

x = (-b ± √(b² - 4(a)(c))) / 2(a) **

x = (-b ± √(b² - 4ac) /(2a)
>comments on someones inability to use order of operations
>writes the equation with the order of operations wrong twice

Not sure if the lack of parenthesis is acceptable or not, in your equation, can you get back to me on that, I'm curious :D Pic unrelated

It's not.


Without the parenthesis you divide by 2 and then multiply by a.
With parenthesis you divide by 2a

when "typing" math, it's usually acceptable to exclude the brackets in the denominator if there is a space between the divisor and the division sign.

i mean the one in the first half of the equation where you have only 1 ) at the end before the divide.

youre second one is correct. but it's less ambiguous if you include the brackets.

I'll do better than that, I'll explain why it works.
A general quadratic equation is Ax² + Bx + C = 0 (equating to zero to find a root)
divide by A is x² + (B/A)x + C/A = 0 we can use this to complete the square
[x+B/(2A)]² - (B/(2A))² + C/A=0
[x+B/(2A)]² = C/A + B² /(4A² ) now we need to make the right a single fraction
[x+B/(2A)]² = (4AC + B² )/(4A² ) now square root both sides
x+B/(2A) = [±√(4AC+B² )]/(2A)
so... x = -B/2A ±√(4AC+B² )]/(2A) = [-B ±√(4AC+B² )]/(2A)

easy

I think Marvin is a nice name. Maybe Chester.

Looks like a mcdonalds application to me

When I first got my graphing calculator, (and I'm sure plenty of you have done this, too) I just programmed the quadratic formula into the functions and all I had to do was provide A, B, & C, and it would give me the answer(s). Teachers were baffled at how fast I went through those problems...

The programming differs slightly depending on the calculator, but should work for most TI's. Might have to adjust the program a bit. Here we go.

Create a new program on your calculator. This is done by pushing the "PRGM" button on your calculator, then scrolling over to "New." Hit "Enter" to create a new program. Title the program "QUADFORM."
Press "PRGM" then scroll to "I/O" and press 3 to get "DISP." Then press "2nd" "Alpha" to Alpha Lock your calculator and type "ENTER A" (make sure you include the quotation marks on each side of ENTER A).
Press "PRGM" then scroll to "I/O" and press 1 to get "Input." Then press "Alpha" and "Math" to get the letter A to appear. You do not need quotation marks around the A in this case.
Repeat steps 2 and 3 two more times, replacing A with B and then with C so the next four lines in the calculator program read: Disp "ENTER B", Input B, Disp "ENTER C", Input C.
Type in the square root followed by B^2-4AC)->D. The square root will automatically open parenthesis for you, so you will need to close them after the C. The B^2 can be input as B^2 or as B squared. The -> sign is found above the "ON" button where it says "STO->".
Press in the following: (-B)/(2A)->I. Where the - before the B is the negative sign, NOT the minus sign.
Type in the following on the next line: (D)/(2A)->F Then type in the following on the line after that: (-D)/(2A)->S
Press "PRGM" then scroll over to "I/O" and press 3 for "Disp." Then type in I+F, I+S. This will give you the results of the quadratic formula when you use the program.

Billy!

QUADRATIC

I shall call it Snuggly-buns and I will love it and hold it to the death!

quadratic formula

In danish this is known as "The idiot formula",
apparently because, id you do not memorize this you are an idiot
Seriously

LOL that is some pussy shit, that was taught in my 7th grade math class.

f(x) = e^x

find the 3724th derivative. go.

well the 3724 derivative of e^x is: e^x

honestly, i have never seen your formula before so idk what it relates to

nothing because it's wrong



noob

Squishy, I shall name him squishy and he shall be my squishy.

Sounds aboout right.

It's to determine the discriminant, right?

no it's actually just b² - 4ac.

SMH when i'm a math teacher and i just got thumbed down for posting the correct discriminant

yeah you're right, most people seemed to miss the blatantly offensive errors in the so called quadratic :P

haha, you're fucked

this backfired...

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You are cancer.

Those were over a good length of time
nice try

no. bad cancer cell.
what about this shit.

you missed the best part

oh shit nigger nice roll.
still a bit spammy

thanks, and I see where your coming from.

Like a total bad ass.


=D

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<-- Teachers face