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Comments(90):
What do you think? Give us your opinion. Anonymous comments allowed.
#26

sorenlolz ONLINE (01/27/2013) []
This really make me want to buy a pie right now, DAMN YOU Teranin
#16

mallet (01/27/2013) []
look there's pi in the pie
it makes me wonder why
why that pi in the pie
makes me wanna love you
it makes me wonder why
why that pi in the pie
makes me wanna love you
#31 to #13

xxxsonic fanxxx (01/27/2013) []
Mathfag here, that's actually not known. It's conjectured that every possible combination of digits appears in pi's decimal expansion (that's called being a "normal" number), but it hasn't been proven, and it doesn't follow from the fact that it's infinite and nonrepeating. And to the people saying certain number combinations are impossible: no they're not, they're just unlikely.
#25 to #17

BobbyMcFerrin (01/27/2013) []
i can't supply a proof but i would venture a guess that certain number combinations are impossible. for example, 50,000,000 zeroes side by side. There may be a proof out there that shows that numbers cannot repeat past a certain amount due to the nature of the calculation. idk for sure though
#63 to #48

BobbyMcFerrin (01/27/2013) []
The string 000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 did not occur in the first 200000000 digits of pi after position 0.
(Sorry! Don't give up, Pi contains lots of other cool strings.)
doesn't mean it doesn't exist...but there may be a proof along the lines of Fermat that shows for the calculation of pi using an ngon with n approaching infinity, since it involves square roots, that no set of consecutive square roots can be summed to give a string of 'x' zeroes.
like i said, such a proof may not exist, but if it did my guess is it would look something like that
(Sorry! Don't give up, Pi contains lots of other cool strings.)
doesn't mean it doesn't exist...but there may be a proof along the lines of Fermat that shows for the calculation of pi using an ngon with n approaching infinity, since it involves square roots, that no set of consecutive square roots can be summed to give a string of 'x' zeroes.
like i said, such a proof may not exist, but if it did my guess is it would look something like that
#7

zzforrest (01/26/2013) []
What is a transcendental number anyway? I'd really like to know since I can't seem to find anybody who can explain it to me.
#8 to #7

xxxsonic fanxxx (01/26/2013) []
Simply put, a transcendental number has two properties. The first being that it must be irrational, i.e. it cannot be expressed as a fraction. The second is that it cannot be the solution to an equation with rational coefficients. For example, both pi and e are transcendental for these reasons but sqrt(2) is not because while it cannot be expressed as a fraction, it is the solution to the equation x^22=0
Wikipedia
Wikipedia