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What do you think? Give us your opinion. Anonymous comments allowed.
#98

anonymous (12/05/2012) []
Funnyjunk understands math, But they get worked up about the Captcha code recieving one more number.
#77

anonymous (11/30/2012) []
beautiful moment when that's the gravitional potential of the earth :')
#24

kusalranawaka (11/30/2012) [] MFW when im studying circuar motion and gravitaional forces right now
#61 to #59

kusalranawaka (11/30/2012) [] He tried to embarrass me by insinuating I was a liar.
I gave him a legitimate answer.
He failed to embarrass me.
So im asking if hes mad i ruined his plot...
problem?
I gave him a legitimate answer.
He failed to embarrass me.
So im asking if hes mad i ruined his plot...
problem?
#20

solrosen (11/30/2012) []
**solrosen rolled a random image posted in comment #2 at Tittysprinkles ** MFW math
#22 to #21

solrosen (11/30/2012) []
**solrosen rolled a random image posted in comment #216 at All night erry night **
I repeat, MFW math. :I
I repeat, MFW math. :I
#17

anonymous (11/30/2012) []
a=GM/R^2
M=a*r^2/G
1*5^2/6.67*10^11 = 2.8*10^11 kg
I think. Haven't done Physics for about a year.
M=a*r^2/G
1*5^2/6.67*10^11 = 2.8*10^11 kg
I think. Haven't done Physics for about a year.
#7

TheBarneyStinson (11/30/2012) []
(mv^2/r)=(Gmm/r^2)
(mv^2/r)=(Gmm/r^2)
(v^2)=(Gm/r)
(rv^2)=(Gm)
(rv^2/G)=(m)
5(1^2)/6.67E11=m
m=74962518740.6
m=7E10
(
(v^2)=(Gm/r)
(rv^2)=(Gm)
(rv^2/G)=(m)
5(1^2)/6.67E11=m
m=74962518740.6
m=7E10
#8 to #7

TheBarneyStinson (11/30/2012) []
*kg
And I hate to be "that dick" that tries to show off his math skills any time the subject comes up, but this is actually the exact unit I'm studying in physics, and this actually kind of helped me.
And I hate to be "that dick" that tries to show off his math skills any time the subject comes up, but this is actually the exact unit I'm studying in physics, and this actually kind of helped me.
#10 to #8

physicsdude (11/30/2012) []
You are given the acceleration a=1 m/s^2. You use the given acceleration as velocity which is wrong.
Use the formula: F=ma=GMm/r^2 giving:
a=GM/r^2
M=a*r^2/G
M= 1*5^2/6.67*10^11=2.8*10^11 kg
Sorry to be THAT DICK that tries to show off his math skills(though you didn't fail on the math just understanding the physics) any time some one makes a misscalculation. mistakes
Use the formula: F=ma=GMm/r^2 giving:
a=GM/r^2
M=a*r^2/G
M= 1*5^2/6.67*10^11=2.8*10^11 kg
Sorry to be THAT DICK that tries to show off his math skills(though you didn't fail on the math just understanding the physics) any time some one makes a misscalculation. mistakes
#30 to #29

physicsdude (11/30/2012) []
Indeed. Though he stated "this is actually the exact unit I'm studying in physics". Which leads me to believe that he should know about this stuff. I learned this in the danish equivalent of highschool, so to be that far off when you study it.
#91 to #30

TheBarneyStinson (11/30/2012) []
I missed a really important day of class when I was in Vancouver, so I don't totally know what I'm doing. Thanks for helping me!
#25 to #10

ReyJavikVI (11/30/2012) []
While you did use the correct formula, I don't know how you got 25/6.67 = 2.8. The mass is 3.75*10^11 kg. According to Wikipedia, that's around the mass of the whole human species.
So yeah, yo momma so fat she weighs more than all the other mommas in the world.
So yeah, yo momma so fat she weighs more than all the other mommas in the world.
#26 to #25

physicsdude (11/30/2012) []
I honestly have no idea how I've managed that. Cudos for correcting it.
#11 to #10

physicsdude (11/30/2012) []
My grammar is off by miles.. But atleast i know physics. Yay for nothing usefull
#12 to #4

physicsdude (11/30/2012) []
Not at all. Any huge object can be seen as a point of mass at its center of mass when calculating the gravitational pull.
For example when calculating the earths gravitational pull, you take the entire mass of the earth and use its center as the point. So it is calculated as if it is simply a point of mass. This is the same for ANY object.
For example when calculating the earths gravitational pull, you take the entire mass of the earth and use its center as the point. So it is calculated as if it is simply a point of mass. This is the same for ANY object.