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#25 - anonymous (09/14/2013) [-]
Anyone who wants to understand this need only search Euler's Rule. e^(i θ) = cos θ + isin θ . In this case, θ = 180* so you get cos θ is equal to -1 and isin θ equal to zero.
User avatar #97 to #25 - revisandbutthead (09/14/2013) [-]
For something even cooler, use Euler's identity and plug in π/2.

e^(πi/2) = cos π/2 +isin π/2

e^(πi/2) = 0 + i

Raise both sides by i.

e^(πi^2/2) = i^i

i^i = e^(-π/2)

So √-1 raised to the √-1 power is a real number. e^(-π/2)≈0.20788
#53 to #25 - atheistmatt (09/14/2013) [-]
Thank you, I was hoping someone eventually said this. Also fun enough, e^i(tau) = 1, only because it is simply 2pi, just another fun fact because Euler's Rule is awesome.

I thought stuff like the identities were more commonly known...
#54 to #53 - atheistmatt (09/14/2013) [-]
oh and thumbs for everyone
#26 to #25 - anonymous (09/14/2013) [-]
oh right its an i, I thought it was a 2 with a suspicious dot
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