in order for there to be an exact answer it needs to be written more explicitly.
Some places it is taught to go left to right when two operations have the same priority others it's right to left. Use more parentheses or brackets and you will be able to make an equation that has only one solution.
BEDMAS ******
Brackets first
Then Exponents
Then Division or Multiplication, which ever comes first in the equation
Then Addition or Subtraction, which ever comes first in the equation
we learned it BEDMAS which puts division before multiplication in your case... you do it in the ORDER of when they appear when practicing ORDER of operations.
The orders of operations puts multiplication and division on equal level.
Any division of a number by another number is the same as the multiplication of the first number by the reciprocal number. Similarly, a number minus another is the same as the first number plus the negative of the other number. And, the n-root of any number is equal to that number to the power of the reciprocal number.
x - y = x + (-y)
x / y = x * (1 / y)
n-root( x ) = x^(1/n)
Thus, division and multiplication is in some way the same thing, like addition and subtraction, and exponents and roots are the same thing. Thus, putting one before the other really is meaningless. Parentheses are before exponents and roots, that are before multiplications and divisions, that are before additions and subtractions.
I found the answer is 9...
now some people may say "you have to solve the brackets and simplify that first" but here's the thing: shut uppa with the shut uppa, you solve everything IN the brackets then treat the result like a regular ass number, which in this case is being multiplyed, however the divide comes first in this equation
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I hate this video
>I don't know how the order of operations works
>I'm still going to talk about it
>Instead of PEMDAS, we should just teach kids about how to solve an equation by teaching them which order the operations go in
Smartass who didn't pay attention in class when they explain PEMDAS to you.
The divide sign is not used in higher arthimatic, specifically because it causes difficulty in determing the correct order of operations.
If the equation was written correctly it would have had the 6 as a "fraction" of the rest of the function, allowing you to determine the correct order of operations.
order of operations p e md as, the answer is 9, there is no reason to do 2x3 before doing 6/2, because you solve for multiplacation and division at the same time starting from the left working to the right in the equation
im using a calculator everyday. its just not true. "/" is just multiplying with the inverse of the next argument, therefore the operators / and * have to behave the same way. thats how math do.
Why does this guy have 7 thumbs? He's still wrong.
6/2(1+2)
6/2(3) This is where he ****** up, he multiplied 2 and 3 first when he was supposed to divide 6 and 2
3(3)
9
The problem with this is that it comes down to writing, and then also how it's computed.
On paper, it's 9, because once the bracket is solved, its a regular number, 3, which turns the equation into 6 / 2 X 3 (Following BEDMAS, we get 9).
HOWEVER, when a machine is tasked to solve this, you'll notice EVERYTHING beyond the division line is considered the denominator, which gives us 6 / 6.
It's purposely written like this to **** with you.
it depends.
technically the equation is wrong because the sign for multiplication is missing between "2" and "(1+2)"
but thats not a big problem, because it is taught that it automatically means it gets multiplicated. the little thing to consider here is: the one who wrote the equation. if you write down something like "2*1(1+3)" usually means to first multiplicate the "1" and "(1+3)" and only afterwards do the other multiplication (in this case it wouldnt matter, but in the case of the posting there is a difference)
you always do brackets first.
now this is kinda bad layout but it still shows 2(1+2) as a single entity, if it was (6/2) *(1+2) it would be 9, if it showed 6/2*(1+2) it would be a toss up how you wanted to do it (cos that is awfull format). but because it is 6/2(1+2) it works out as 6/(2*(1+2)) giving you 6/6=1 because as i said at the start you always do brackets firstr
(1+2) in the bracket first, followed by whatever times the bracker which here is 2 then the multiplications/division outside the bracket which here is 6/everything else
resulting as i said in 6/(2*(1+2)) =6/6=1
no because im an engineer who uses maths far more complex then this for a living
you always do brackets first, the way this equation is written is equivalent to 6/(2+4)
because 2(1+2) is always done befor the 6/
Yes, you do what's inside the brackets, you don't multiply into it.
and 2(1+2) = 2*(1+2)
They key to answer this is that you multiply/divide from left to right, they same way that 6-3+3 = 6 and not 0
thats a different case entirely, because there are no brackets in that case its not 6 -(3+3)
its 6+(-3)+3 they are 3 seperate entities as such they dont compound.
whereas 2(1+2) is one entity, as such in the 6/2(1+2) you treat 2(1+2) as (2+4) whereas if it was (6/2)(1+2) it would be 9 because in this case the 6/2 is treated befor the 2(1+2)
All these god damn people fighting over this **** like it matters. There are two answers because the question is formatted to be contradicting and confusing. The argument to be made for 9 is PEMDAS and the argument for 1 is that it's 2(1+2) not 2*(1+3) which have the same result but which are not technically the same. There isn't one correct answer.
Because of the way the 2(1+2) is written my brain wants to group that to one term and then divide 6 by 6 to get 1, but that's wrong, which is really the purpose of the problem.
Incorrect it is 9 you do multiplication/division based of the order in which they appear (After Parenthesis and Exponents of course) not multiplication first then division. I am an accounting major I would not be passing my classes if I didn't understand how to do 3rd grade math
Nope, at that point the parentheses stop mattering and just separate it from the two, telling you that it will be multiplied at some point. The parentheses only matter for numbers inside it, the two is not inside.
Considering I was taught P>E>M=D>A=S. Where essentially multiplication and division are equal in terms of priority except in cases where one comes before the other. In that case it's a first come, first serve basis.
other ways this could be written for the sake of clarity would be
1.
6
--------
2(1+2)
which would equal 1
2.
6/2 x (1+2)
which would equal 9
The problem in question, if done as is should have the questioner dragged out into the street and shot, because they're a massive cunt with no respect towards proper mathematical grammar.
The answer is indeed 9, but all of you are wrong, including some of those who said 9.
Let me tell you why.
First, you need to multiply the contents of the parentheses by any multiplier applied to them. You may remember this being called "Distribution." This is the step you skip to get the wrong 9.
However, it's also the same step people mess up on to get 1. Remember when they talked about expressions? 6/2 is a whole expression. It's all one piece. as a matter of fact, the whole expression is 6/2().
So, you get 3(), and now we can look back at what's in the parentheses.
3(1+2)
3(3)
9
You guys might be getting the right answer anyway, but when variables come into play, the outcome may... Vary.