4chan (4). . 90% of math graduates can' t solve this equation. See what happens here is 10% of "Math Graduates" are retarded and they have a solution for an impossible equation.
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4chan (4)

90% of math
graduates can' t
solve this equation
...
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Views: 31939
Favorited: 68
Submitted: 12/31/2013
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Comments(186):

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User avatar #1 - godtherapist ONLINE (12/31/2013) [+] (14 replies)
See what happens here is 10% of "Math Graduates" are ******* retarded and they have a solution for an impossible equation.
#12 - jakuhlope (12/31/2013) [-]
>yahoo search bar   
>probably using IE
>yahoo search bar
>probably using IE
+42
#2 - fourkids **User deleted account** has deleted their comment [+] (11 replies)
#40 - crazyolitis (01/01/2014) [+] (3 replies)
I've got vacation right now. I refuse to do this **** .
User avatar #3 - edwardtrollington (12/31/2013) [+] (7 replies)
Correct me if I'm wrong, but isn't the answer (positive or negative) infinity? (positive or negative) Infinity plus two is still (positive or negative) infinity.
#8 to #3 - pedobearson (12/31/2013) [-]
Infinity is not a number. Also, infinity plus 2 equals infinity(+2). This question doesn't have an answer.
User avatar #42 - ubisoft (01/01/2014) [-]
It cancels itself out. You need to get y by itself but when you subtract the Ys they cancel and that's it no solution.
#154 - Durp (01/01/2014) [-]
Clearly you're all wrong.
#118 - snickets (01/01/2014) [+] (3 replies)
y+2=y
Since y contains the variable to solve for, move it to the left hand side of the equation by subtracting y from both sides
y+2-y=0
Since y and -y are like terms, add -y to get y to get 0
0+2=0
Remove the 0 from the polynomial, adding or subtracting 0 doesn't change the value of the expression
2=0
Since 2=/=0, there are no solutions
#56 - kambin (01/01/2014) [+] (22 replies)
Let a=b Multiply both sides by a giving:
a*a=a*b Now add a*a to both sides giving:
a*a + a*a = a*a + a*b Or, rewritten:
2a*a = a*a + a*b Now subtract 2a*b from both sides
2a*a - 2a*b = a*a + a*b - 2a*b Combine like terms on right
2a*a - 2a*b = a*a - a*b Factor out the a*a - a*b on each side
2(a*a - a*b) = 1(a*a - a*b) Cancel the (a*a - a*b) from both sides
2=1
#69 to #56 - keifahall (01/01/2014) [-]
Wrong

If a=b Multiplying both sides by a gives:
a*a=a*b which equivalently is
(1) a*a-a*b=0

2(a*a-a*b) =1(a*a-a*b)
substituting equation (1)
2(0) = 1(0)
0=0
#130 - buttholee (01/01/2014) [+] (5 replies)
Or, or, or, or…

y + 2 = y

(y/y) + 2 = (y/y)

2 = 0
#135 to #130 - breadbasket (01/01/2014) [-]
Two
is equal to
zero.


Do you even realize what you've done?
User avatar #80 - buttinspecter (01/01/2014) [+] (2 replies)
y + 2 = y
(y + 2) - y = (y) - y
2 = 0
#166 - furiousmarshmellow (01/01/2014) [-]
That's not a possible equation.
That's not a possible equation.
User avatar #156 - shadowstepone (01/01/2014) [-]
this is physically impossible
that's literally saying 4=6
User avatar #152 - cadencee (01/01/2014) [-]
That's like saying: 'The cat is two inches taller than itself' then expecting a mathematical solution. It's a statement, nothing more.
#68 - notbenstiller **User deleted account** (01/01/2014) [-]
I've never graduated from math.
I've never graduated from math.
User avatar #51 - lasomacintosh (01/01/2014) [+] (21 replies)
Y is equal to infinity because infinity plus 2 is still infinity.
User avatar #54 to #51 - derpityherpity (01/01/2014) [-]
or the equation just has no solution? since infinity isn't an actual number ish thing
#23 - captainstinkypinky (01/01/2014) [+] (10 replies)
y=-2, right?
y=-2, right?


#44 to #23 - plutogekko (01/01/2014) [-]
the answer is "no solution". since the y's negate each other and you're left with 2=0.
User avatar #163 - theswede (01/01/2014) [-]
I'm on winter break, I don't need to see math even if it involves dicks
User avatar #143 - Leopard (01/01/2014) [+] (2 replies)
There is no ******* solution.
#164 to #162 - GamerMandrew (01/01/2014) [-]
The ******* hammer... THE ******* HAMMER!!
#139 - ideae (01/01/2014) [+] (12 replies)
y + 2 = y
y - y = 2
(1-1) y = 2
y=2/(1-1) = 2/0 = lim x -> 1 (x+1)/(x-1) = lim x -> 0 (x+2)/x = 1+ 2/0 = 1 + 2/(2*0) = 1 + 1/0
let u = 1/0, y = 2u = 1+u => u = 1 => y = 2.

Or,

zeta(1) = 1 + ½ + ⅓ + ¼ + 1/5 + 1/6 + 1/7 + ⅛ + 1/9 + … + 1/n + …
= -ln 0

y/2 = ½ + ¼ + 1/6 + ⅛ + … + 1/2n + …

y - 2*y/2 = 1-½+⅓-¼+…+1/n (-1)^(n+1) + … = ln 2
y = (ln 2)/0
let s = 1/0 = 1/(1-1) = 1+1^1+1^2+1^3+1^4+…=1+1+1+1+1+…
let t = ½ = 1/(1-(-1))= 1-1+1-1+1-1+1-1+…
-t = -1+1-1+1-1+1-1+1-…
s - t = 1+1+1+1+1+1+1+1+…
-1+1-1+1-1+1-1+1-1+…
= 2+2+2+2+2+2+2+2+… [summing up each individual term]
= 2s
=> 1/0 = s = -t = -½
=> y = -(ln 2)/2. q.e.d.
User avatar #160 to #139 - guano (01/01/2014) [-]
what dafuq?
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